Photoelectric Effect Revision

A photon with frequency of 1.5 x 10^15 Hz is incident on a piece of metal in the standard photoelectric experimental setup. What is the wavelength of this photon?

• 20 nm

• 150nm

• 200nm

• 500nm

What type of light is this photon?

• Visible

• Infrared

• Ultraviolet

• X Ray

How much energy is carried by this electron?

• 1.33 eV

• 6.21 eV

• 9.7 x 10^-19 J

• 1.33 x 10^-19 J

The same energy in Joules is...

• 1.6 x 10^-19 J

• 3.88 x 10^-19 J

• 6.21 x 10^-19 J

• 9.93 x 10^-19 J

An electron inside the metal has a binding energy of 7.3eV.

• This electron cannot be reached by the UV light.

• This electron can be reached by the UV light, but will not absorb it.

• This electron can be reached by the UV light, will absorb it, but will not escape the metal.

• The electron can be reached by the UV light, will absorb it, and will escape the metal.

A different electron inside the metal has a binding energy of 4.11eV.

• This electron cannot be reached by the UV light.

• This electron can be reached by the UV light, but will not absorb it.

• This electron can be reached by the UV light, will absorb it, but will not escape the metal.

• The electron can be reached by the UV light, will absorb it, and will escape the metal.

How much kinetic energy will it emerge with?

• 2.1eV

• 4.11eV

• 6.21eV

• All energy will be converted to binding energy.

The backvoltage required to definitely stop this electron will be

• 6.21 Volts

• 4.11 Volts

• 2.1 Volts

• 2.01 Volts

The work function for this metal is:

• Less than or equal to 4.11eV

• 4.11eV

• Between 4.11eV and 7.3eV

• Greater than 7.3eV

A wave theory explanation of the photoelectric effect would predict (tick all that apply):

• A brief time delay after the light is turned on and before current begins flowing

• That higher frequency light will cause a larger stopping voltage

• That higher intensity light will cause a larger stopping voltage

• That higher intensity of light will cause a larger saturation current.