writing two variable linear equations 2020

writing two variable linear equations 2020

9th - 12th Grade

14 Qs

quiz-placeholder

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writing two variable linear equations 2020

writing two variable linear equations 2020

Assessment

Quiz

Mathematics

9th - 12th Grade

Medium

CCSS
8.EE.C.8A, 8.EE.C.8B, 8.EE.B.6

+2

Standards-aligned

Created by

Noel Lopez

Used 3+ times

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14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Which equation below is the point slope form?

y = mx + b

y = m(x + b)

y y1 =m(x x1)y\ -\ y_{1\ }=m\left(x\ -x_1\right)

y2 y1x2x1\text{}\frac{y_{2\ }-y_1}{x_2-x_1}

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Which equation is NOT written in standard form?

2x + 3y = 7

4 = -3y + 4x

3y = -2x + 4

y + x = 2

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Given m = -3 and the line is crossing the y-axis at coordinate point ( 0, 6). What would the slope intercept equation be for the line?

y = -3x

y = 6x - 3

y = -3 + 0,6

y = -3x + 6

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

4.

MULTIPLE SELECT QUESTION

15 mins • 1 pt

Given the coordinate points (2, 5) and (-3, -10) mark all equations that would represent the line, written in slope intercept form.

y = 3x - 1

3x - y = 1

y - 5 = 3( x - 2)

-1 + 3x = y

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Given the coordinate points (1, 7) and (-1, 7) what would the slope of this line?

m = 7

m = 0

m is undefined

m = 27m\ =\ \frac{2}{7}

m =02m\ =\frac{0}{2}

Tags

CCSS.8.EE.B.5

6.

MULTIPLE SELECT QUESTION

15 mins • 1 pt

Given the coordinate points (-3, 7) and (1, -1), what would the point-slope form of an equation be for the line going through these two points? Choose all that apply

y + 3 = -2(x - 7)

y + 1 = -2(x -1)

y - 7 = -2 ( x+ 3)

y -1 = -2(x - 1)

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Given the following graph, which slope intercept equation represents the line on the graph?

y=54x 5y=\frac{5}{4}x\ -\ 5

y = 54x + 5y\ =\ \frac{-5}{4}x\ +\ 5

y = 45x + 5y\ =\ \frac{-4}{5}x\ +\ 5

y = 45x 5y\ =\ \frac{4}{5}x\ -\ 5

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