K.D. 3.5: 3. Hubungan bagian lingkaran

$$\frac{<P}{<O}$$  = $$\frac{P\ B}{K\ O}$$  = $$\frac{L\ J\ }{L\ O\ }$$  

$$\frac{<P}{<O}$$ = $$\frac{P\ B}{K\ O}$$

K O = $$\frac{<O}{<P}$$ X P B

= $$\frac{360}{60}$$  X 64 cm

= 6 X 64 cm

= 384 cm

$$\frac{<P}{<O}$$  = $$\frac{P\ B}{K\ O}$$  = $$\frac{L\ J\ }{L\ O\ }$$  

$$\frac{<P}{<O}$$ = $$\frac{L\ J}{L\ O}$$

L O = $$\frac{<O}{<P}$$ X L J

= $$\frac{360}{60}$$  X 80 cm²

= 6 X 80 cm²

= 480 cm²

$$\frac{<P}{<O}$$  = $$\frac{P\ B}{K\ O}$$  = $$\frac{L\ J\ }{L\ O\ }$$  

K O = π d = π 2r

= 22/7 X 2 X 21 cm

(7 dan 21 saling bagi)

= 22 X 2 X 3 cm

= 132 cm

P B = $$\frac{<P}{<O}$$   X K O

= $$\frac{60}{360}$$   X 132 cm

(60 dan 360 saling bagi)

= 1/6 X 132 cm

(6 dan 132 saling bagi)

= 22 cm

$$\frac{<P}{<O}$$  = $$\frac{P\ B}{K\ O}$$  = $$\frac{L\ J\ }{L\ O\ }$$  

$$\frac{<P}{<O}$$ = $$\frac{P\ B}{K\ O}$$

K O = $$\frac{<O}{<P}$$ X P B

= $$\frac{360}{30}$$  X 11 cm

(360 dan 30 saling bagi)

= 12 X 11 cm

= 132 cm

K O = π d = 132 cm

d = 132 X 7/22

(132 dan 22 saling bagi)

= 6 X 7

= 42 cm

r = ½ d

= ½ 42 cm

= 21 cm

$$\frac{<P}{<O}$$  = $$\frac{P\ B}{K\ O}$$  = $$\frac{L\ J\ }{L\ O\ }$$  

$$\frac{<P}{<O}$$ = $$\frac{L\ J}{L\ O}$$

L O = $$\frac{<O}{<P}$$ X L J

= $$\frac{360}{90}$$  X 616 cm²

= 4 X 616 cm²

= 2.464 cm²

L O = π r² = 2.464 cm²

r² = 2.464 X 7/22

(2.464 dan 22 saling bagi)

= 112 X 7

= 784

r = √ 784

= 28