Soal Penerapan Fungsi Trigonometri (Kecekungan Kurva)

Soal Penerapan Fungsi Trigonometri (Kecekungan Kurva)

Assessment

Quiz

Mathematics

12th Grade

Medium

CCSS
HSF-IF.C.7E

Standards-aligned

Created by

Ajun nahar 8D

Used 7+ times

FREE Resource

Student preview

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Turunan kedua dari fungsi f(x)=sin2x2x3f\left(x\right)=\sin^2x-2x^3  adalah ....

 2sin2x12x-2\sin^2x-12x  

 2sin2x+6x2-2\sin2x+6x^2  

 2sin2x6x22\sin2x-6x^2  

 2cos2x12x-2\cos2x-12x  

 2cos2x12x2\cos2x-12x  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Salah satu titik balik maksimum dari grafik fungsi f(x)=3sin2xf\left(x\right)=3\sin2x adalah .... 

 (π4,3)\left(\frac{\pi}{4},-3\right)  

 (3π4,3)\left(\frac{3\pi}{4},3\right)  

 (5π4,3)\left(\frac{5\pi}{4},3\right)  

 (3π2,3)\left(\frac{3\pi}{2},3\right)  

 (7π4,3)\left(\frac{7\pi}{4},3\right)  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Fungsi f(x)=cos2x5f\left(x\right)=\cos2x-5  untuk  0<x<2π0<x<2\pi  turun pada interval ....

 0<x<π20<x<\frac{\pi}{2}  atau  3π2<x<2π\frac{3\pi}{2}<x<2\pi  

 π<x<3π2\pi<x<\frac{3\pi}{2}  

 π<x<2π\pi<x<2\pi  

 0<x<π20<x<\frac{\pi}{2}  atau  π<x<3π2\pi<x<\frac{3\pi}{2}  

 π2<x<π\frac{\pi}{2}<x<\pi  atau  3π2<x<2π\frac{3\pi}{2}<x<2\pi  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui fungsi f(x)=3cos2x+1f\left(x\right)=-3\cos2x+1  dengan  0<x<2π0<x<2\pi  .  Salah satu titik belok fungsi tersebut adalah ....

 (5π3,52)\left(\frac{5\pi}{3},\frac{5}{2}\right)  

 (5π4,1)\left(\frac{5\pi}{4},1\right)  

 (3π2,4)\left(\frac{3\pi}{2},4\right)  

 (2π3,114)\left(\frac{2\pi}{3},\frac{11}{4}\right)  

 (π2,2)\left(\frac{\pi}{2},2\right)  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui fungsi f(x)=12sin2x+1f\left(x\right)=\frac{1}{2}\sin2x+1  dengan  0°<x<360°0\degree<x<360\degree  .  Kurva  f(x)f\left(x\right)  akan cekung ke atas pada interval ....

 0°<x<90°0\degree<x<90\degree  

 45°<x<225°45\degree<x<225\degree  

 90°<x<180° 90\degree<x<180\degree\   atau  270°<x<360°270\degree<x<360\degree  

 0°<x<90°0\degree<x<90\degree  atau  180°<x<270°180\degree<x<270\degree  

 180°<x<225°180\degree<x<225\degree  atau  225°<x<360°225\degree<x<360\degree  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Suatu gelombang bergerak mengikuti model : s(t)=12cos4x2sin4xs\left(t\right)=\frac{1}{2}\cos4x-2\sin4x .  Percepatan gelombang saat  t=π4t=\frac{\pi}{4}   adalah ... 

 4-4  

 22  

 55  

 77  

 88  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Fungsi f(x)=2sin(xπ4)f\left(x\right)=2\sin\left(x-\frac{\pi}{4}\right)  mempunyai daerah asal  0x2π0\le x\le2\pi  . Fungsi tersebut cekung ke bawah pada interval .... 


 π4<x<3π4\frac{\pi}{4}<x<\frac{3\pi}{4}  

 π4<x<5π4\frac{\pi}{4}<x<\frac{5\pi}{4}  

 π4<x<2π\frac{\pi}{4}<x<2\pi  

 x<π4 atau x>3π4x<\frac{\pi}{4}\ atau\ x>\frac{3\pi}{4}  

 x<π4 atau x>5π4x<\frac{\pi}{4}\ atau\ x>\frac{5\pi}{4}  

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