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2A.2A Absolute Value Graphs and Transformations

Authored by Audrey Elliott

Mathematics

10th - 12th Grade

CCSS covered

Used 64+ times

2A.2A Absolute Value Graphs and Transformations
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20 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the domain and range of the graph?

Domain:

[,+]\left[-\infty,+\infty\right] Range: [3,+]\left[-3,+\infty\right]

Domain: (,+)\left(-\infty,+\infty\right) Range: [3,+)\left[-3,+\infty\right)

Domain: [3,+)\left[-3,+\infty\right) Range: all real numbers

Domain: (,3]\left(-\infty,3\right] Range: (,+)\left(-\infty,+\infty\right)

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the vertex of the graph?

  \  

(2, -3) 

(2,3)

(-2, -3) 

(-2, 3) 

Tags

CCSS.HSF-IF.C.7D

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What are the x intercepts? (Write as coordinates!)

(-5, 0) & (1, 0)

(0, -5) & (0, 1)

(0, -1) & (0, 1)

(-2, -3) & (0, -1)

Tags

CCSS.HSF-IF.C.7D

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the y intercept?

(-2, -3)

(0, -1)

(-1, 0)

(-5, 0)

Tags

CCSS.HSF-IF.C.7D

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given the parent function

 y=xy=\left|x\right|  what would be the equation of a function with a horizontal shift left 4 units and a vertical stretch by a factor of 5? 

 y=15x+4y=\frac{1}{5}\left|x+4\right|  

 y=5x+4y=5\left|x+4\right|  

 y=5x4y=5\left|x-4\right|  

 y=15x4y=\frac{1}{5}\left|x-4\right|  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given the parent function

 y=xy=\left|x\right|  what would be the equation of the function that had a vertical shift down 1, a horizontal shift right 3, and is reflected across the x axis. 

 y=x31y=\left|x-3\right|-1  

 y=x+31y=-\left|x+3\right|-1  

 y=x31y=-\left|x-3\right|-1  

 y=x+31y=\left|x+3\right|-1  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given the absolute value equation

 y=x1+4y=\left|x-1\right|+4  , what would be the new equation if it were vertically compressed by a factor of 1/3 and has a vertical shift down 2

 y=3x12y=3\left|x-1\right|-2  

 y=3x1+2y=3\left|x-1\right|+2  

 y=13x12y=\frac{1}{3}\left|x-1\right|-2  

 y=13x1+2y=\frac{1}{3}\left|x-1\right|+2  

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