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Similar Figures - Creating Proportions

Authored by Katrina Halloran

Mathematics

7th - 8th Grade

CCSS covered

Used 186+ times

Similar Figures - Creating Proportions
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10 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Use the similar figures shown to identify which side corresponds to side  EF‾\overline{EF}  .

 AB‾\overline{AB}  

 BC‾\overline{BC}  

 CA‾\overline{CA}  

 DF‾\overline{DF}  

Tags

CCSS.HSG.SRT.A.2

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Use the similar figures image shown to identify which angle corresponds to <D<D .

 <E<E  

 <F<F  

 <G<G  

 <H<H 

Tags

CCSS.8.G.A.2

CCSS.HSG.CO.B.6

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Quad TQRS∼BCDETQRS\sim BCDE . Which would be a set of corresponding sides?

TQ‾\overline{TQ} and BE‾\overline{BE}

TS‾\overline{TS} and CD‾\overline{CD}

RS‾\overline{RS} and BC‾\overline{BC}

QR‾\overline{QR} and CD‾\overline{CD}

Tags

CCSS.HSG.SRT.A.2

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

 ΔPQR∼ΔDEF\Delta PQR\sim\Delta DEF . Which describes the relationship between the corresponding sides of the two triangles?

PQDE=46\frac{PQ}{DE}=\frac{4}{6}

PQDE=64\frac{PQ}{DE}=\frac{6}{4}

PQEF=49\frac{PQ}{EF}=\frac{4}{9}

PRDE=66\frac{PR}{DE}=\frac{6}{6}

Tags

CCSS.HSG.SRT.A.2

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

 ΔPQR∼ΔSTU\Delta PQR\sim\Delta STU . Which proportion can be used to solve for n?

 515=n12\frac{5}{15}=\frac{n}{12}  

 155=n12\frac{15}{5}=\frac{n}{12}  

 13n=1236\frac{13}{n}=\frac{12}{36}  

 13n=3612\frac{13}{n}=\frac{36}{12}  

Tags

CCSS.HSG.SRT.A.2

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

 ΔABC\Delta ABC and ΔDEF\Delta DEF are shown. Which statement is true?

 ΔABC∼ΔFDE\Delta ABC\sim\Delta FDE  

 ABCB=DEFE\frac{AB}{CB}=\frac{DE}{FE}  

 <B≅<D<B\cong<D  

 ABAC=DFDE\frac{AB}{AC}=\frac{DF}{DE}  

Tags

CCSS.HSG.SRT.A.2

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

 ΔMNP∼ΔRST.\Delta MNP\sim\Delta RST. Which statement is true?

 <M=<N<M=<N  

 MP10=54\frac{MP}{10}=\frac{5}{4}  

 <N=<R<N=<R  

 RS5=1210\frac{RS}{5}=\frac{12}{10}  

Tags

CCSS.HSG.SRT.A.2

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