Universal Gravity Questions

Calculate the force of gravity on a 500 kg object that is placed on Mars. Mars has a mass of 6.4 x 10^ 23 kg and are separated from the centers of mass at a distance of 3.39 x 10^6 m.

• 1857.28 N

• 2.134 x10¹⁶ N

• 6296 N

Answer explanation

Equation

Fg = (Gm1m2)/r2

Substitute

Fg=(6.67E^-11)(500)(6.4E23) / (3.39E6)²

A 5000 kg object is placed 2m from a 2000 kg object. Calculate the gravitational force between the two objects.

Dont forget the Universal Gravitational Constant "G" 6.67x10^-11. Use the Formula Fg=Gm₁m₂/r²

• 16675 N

• 0.00667 N

• 0.00016675 N

• 0.0003335 N

What is the magnitude for the Big "G"

• 9.81 m/s²

• 6.67 x 10^-11

• 5.85 N

Choose the three variables you multiply together first?

• M1

• M2

• g =9.8 m/s²

• G = 6.67E-11

• r²

Do you divide r² before or after you multiply the numerators together?

• before

• after

Do you divide by r or r²

• r

• r²

Do you multiply two or three numbers together in the numerator?

• two

• three

The unit "kg" kilograms, is a measurement of..

• mass

• time

• gravity

• distance

Tags

NGSS.MS-PS3-1

NGSS.MS-PS3-4

What unit do we use to indicate a measurement of Force?

• m/s²

• Newtons (N)

• Watts (W)

• kg (kilograms)

Tags

NGSS.MS-PS2-1

NGSS.MS-PS2-2

What is the value of the little "g" ?

• 9.81 m/s²

• 6.67E^-11