Test: Module 4

• a and b

• c and e

• c and d

• d and e

• 3) Reflexive Property, 4)

  $m\angle5=m\angle5$

• 3) Transitive Property, 4) $m\angle5=m\angle5$

• 3) Substitution Property, 4) $m\angle3=m\angle4$

• 3) Transitive Property, 4) Reflexive Property

Enter the degree measure that completes the equation $m\angle BCD=$  

Ricardo is copying angle BCD. What is the next step in Ricardo's construction?

• Draw an arc and label the intersection point V.

• Place the point of the compass on point Y and adjust the width to point X.

• Draw TU and point R on TU.

• Draw VU and point R on VU.

Complete the proof by choosing the correct reasons to the table for lines 3 and 6.

• Reason 3: Vertical angles are congruent.; Reason 6: Vertical angles are congruent.

• Reason 3: If two parallel lines are cut by a transversal, the corresponding angles are congruent.; Reason 6: If two parallel lines are cut by a transversal, the alternate interior angles are congruent.

• Reason 3: Vertical angles are congruent.; Reason 6: If two parallel lines are cut by a transversal, the alternate interior angles are congruent.

• Reason 3: If two parallel lines are cut by a transversal, alternate interior angles are congruent.; Reason 6: If two parallel lines are cut by a transversal the corresponding angles are congruent.

Choose the correct statement and reason for line 2 and line 3 in the table to complete the proof. Select ALL that apply.

• Statement 2: $\angle DAB\cong\angle ABC$ ; Reason 2: If two parallel lines are cut by a transversal, then the alternate interior angles are congruent.

• Statement 3: $\angle EAC\cong\angle ACB$ ; Reason 3: If two parallel lines are cut by a transversal, the alternate interior angles are congruent.

• Statement 2: $\angle EAC\cong\angle ACB$ ; Reason 2: If two parallel lines are cut by a transversal, then the alternate interior angles are congruent.

• Statement 3: $\angle DAB\cong\angle ABC$ ; Reason 3: If two parallel lines are cut by a transversal, the alternate interior angles are congruent.

Find the equation of the given line that is perpendicular to the given line and passes through the given point.

 $y=-\frac{1}{3}x-5;\ \left(12,\ 0\right)$  

•  $y=3x-36$  

•  $y=-\frac{1}{3}x-36$  

•  $y=\frac{1}{3}x+36$  

•  $y=\frac{1}{3}x-36$  

Which of the following equations represents a line that is perpendicular to the lines represented by

 $-3x+9y=18$ ? 

•  $-3x+y=6$  

•  $3x+y=-7$  

•  $-x+3y=18$  

•  $-x+3y=6$  

The equation for line A is $y=-\frac{2}{3}x-4$ . Line A and line B are perpendicular and the point $\left(-2,\ 1\right)$ lies on line B. Choose one correct equation for line B.  

•  $y=-\frac{3}{2}x+4$  

•  $y=\frac{2}{3}x+4$  

•  $y=\frac{2}{3}x-4$  

•  $y=\frac{3}{2}x+4$  

Which of the following equations represents the line passing through the point $\left(3,\ -5\right)$ and is parallel to the line containing the points $\left(1,\ 4\right)$ and $\left(3,\ -2\right)$ ?   

•  $x-3y=18$  

•  $x-3y=-18$  

•  $3x+y=4$  

•  $3x-y=14$