Unit 4A Review

Which best represents the function whose graph is shown?

• y = x² + 4x + 7

• y = x² + 2x – 4

• y = x² – 4x + 7

• y = x² – 2x – 4

What are the solutions to the equation that is graphed?

• { -3, -1, 3}

• {-3, -1}

• { -3}

• {-1,3}

Identify the y-intercept and the axis of symmetry for the graph of f(x) = –3x² + 6x + 12.

• 2; x = –12

• 12; x = 1

• –2; x = 0

• –12; x = –1

Determine whether f(x) = –5x² – 10x + 6 has a maximum or a minimum value and find that value.

• minimum; –1

• maximum; –1

• minimum; 11

• maximum; 11

Subtract two complex numbers below

(15 – 13i), (–1 + 17i)

• 16 + 4i

• 16 + 30i

• 16 – 30i

• 46

Tags

CCSS.HSN.CN.A.2

Find the quotient of (1 + 2i) and (2 - 3i).

• $\frac{8}{7}+\frac{1}{7}i$
  

• $\frac{8}{7}+i$

• $-4+7i$

• $-\frac{4}{13}+\frac{7}{13}i$

Which quadratic equation has roots –2 and 3?

• x² + x + 6 = 0

• x² – x – 6 = 0

• x² – 6x + 1 = 0

• x² + x – 6 = 0

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Find the product of these two complex numbers below.

(5 + 2i), (1 + 3i)

• 5 + 6i

• –1

• –1 + 17i

• 11 + 17i

Tags

CCSS.HSN.CN.A.2

ELECTRICITY The total impedance of a series circuit is the sum of the impedances of all parts of the circuit. A technician determined that the impedance of the first part of a particular circuit was 2 + 5j ohms. The impedance of the remaining part of the circuit was 3 – 2j ohms. What was the total impedance of the circuit?

• 5 + 3j ohms

• 5 + 7j ohms

• –1 + 7j ohms

• 16 + 11j ohms

Solve 18x² + 15 = 39x by factoring.

Keep your answers as simplest fractions (No decimals).

(a)  

Tags

CCSS.HSA-REI.B.4B