0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 sin ⁡ θ = 1 2 \sin\theta=\frac{1}{2} sin θ = 2 1

θ = π 6 , 5 6 π \theta=\frac{\pi}{6}\ ,\ \frac{5}{6}\pi θ = 6 π , 6 5 π

θ = π 6 , 11 6 π \theta=\frac{\pi}{6}\ ,\ \frac{11}{6}\pi θ = 6 π , 6 1 1 π

θ = π 3 , 5 3 π \theta=\frac{\pi}{3}\ ,\ \frac{5}{3}\pi θ = 3 π , 3 5 π

θ = 5 6 π , 7 6 π \theta=\frac{5}{6}\pi\ ,\ \frac{7}{6}\pi θ = 6 5 π , 6 7 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 cos ⁡ θ = 1 2 \cos\theta=\frac{1}{2} cos θ = 2 1

θ = π 3 , 5 3 π \theta=\frac{\pi}{3}\ ,\ \frac{5}{3}\pi θ = 3 π , 3 5 π

θ = π 6 , 11 6 π \theta=\frac{\pi}{6}\ ,\ \frac{11}{6}\pi θ = 6 π , 6 1 1 π

θ = π 3 , 2 3 π \theta=\frac{\pi}{3}\ ,\ \frac{2}{3}\pi θ = 3 π , 3 2 π

θ = 2 3 π , 4 3 π \theta=\frac{2}{3}\pi\ ,\ \frac{4}{3}\pi θ = 3 2 π , 3 4 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 tan ⁡ θ = 1 \tan\theta=1 tan θ = 1

θ = π 4 , 5 4 π \theta=\frac{\pi}{4}\ ,\ \frac{5}{4}\pi θ = 4 π , 4 5 π

θ = 3 4 π , 5 4 π \theta=\frac{3}{4}\pi\ ,\ \frac{5}{4}\pi θ = 4 3 π , 4 5 π

θ = 3 4 π , 7 4 π \theta=\frac{3}{4}\pi\ ,\ \frac{7}{4}\pi θ = 4 3 π , 4 7 π

θ = π 4 , 3 4 π \theta=\frac{\pi}{4}\ ,\ \frac{3}{4}\pi θ = 4 π , 4 3 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 sin ⁡ θ = 0 \sin\theta=0 sin θ = 0

θ = 0 , π \theta=0\ ,\ \pi θ = 0 , π

θ = π 2 , 3 2 π \theta=\frac{\pi}{2}\ ,\ \frac{3}{2}\pi θ = 2 π , 2 3 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 cos ⁡ θ = − 1 \cos\theta=-1 cos θ = − 1

θ = 0 , π \theta=0\ ,\ \pi θ = 0 , π

θ = π 2 \theta=\frac{\pi}{2} θ = 2 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 sin ⁡ θ = − 1 2 \sin\theta=-\frac{1}{\sqrt{2}} sin θ = − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

θ = 5 4 π , 7 4 π \theta=\frac{5}{4}\pi\ ,\ \frac{7}{4}\pi θ = 4 5 π , 4 7 π

θ = π 4 , 3 4 π \theta=\frac{\pi}{4}\ ,\ \frac{3}{4}\pi θ = 4 π , 4 3 π

θ = 3 4 π , 5 4 π \theta=\frac{3}{4}\pi\ ,\ \frac{5}{4}\pi θ = 4 3 π , 4 5 π

θ = π 4 , 7 4 π \theta=\frac{\pi}{4}\ ,\ \frac{7}{4}\pi θ = 4 π , 4 7 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 cos ⁡ θ = − 3 2 \cos\theta=-\frac{\sqrt{3}}{2} cos θ = − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

θ = 5 6 π , 7 6 π \theta=\frac{5}{6}\pi\ ,\ \frac{7}{6}\pi θ = 6 5 π , 6 7 π

θ = π 6 , 11 6 π \theta=\frac{\pi}{6}\ ,\ \frac{11}{6}\pi θ = 6 π , 6 1 1 π

θ = π 6 , 5 6 π \theta=\frac{\pi}{6}\ ,\ \frac{5}{6}\pi θ = 6 π , 6 5 π

θ = 7 6 π , 11 6 π \theta=\frac{7}{6}\pi\ ,\ \frac{11}{6}\pi θ = 6 7 π , 6 1 1 π

0 ≤ θ < 2 π 0\le\theta<2\pi 0 ≤ θ < 2 π のとき、次の方程式を満たす θ \theta θ を求めよ。 tan ⁡ θ = − 3 \tan\theta=-\sqrt{3} tan θ = − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

θ = 2 3 π , 5 3 π \theta=\frac{2}{3}\pi\ ,\ \frac{5}{3}\pi θ = 3 2 π , 3 5 π

θ = 2 3 π , 4 3 π \theta=\frac{2}{3}\pi\ ,\ \frac{4}{3}\pi θ = 3 2 π , 3 4 π

θ = π 3 , 4 3 π \theta=\frac{\pi}{3}\ ,\ \frac{4}{3}\pi θ = 3 π , 3 4 π

三角方程式①

Authored by toshihiro sakata

Mathematics

11th Grade

Used 12+ times

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\sin\theta=\frac{1}{2}$

$\theta=\frac{\pi}{6}\ ,\ \frac{11}{6}\pi$

$\theta=\frac{\pi}{6}\ ,\ \frac{5}{6}\pi$

$\theta=\frac{\pi}{3}\ ,\ \frac{5}{3}\pi$

$\theta=\frac{5}{6}\pi\ ,\ \frac{7}{6}\pi$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\cos\theta=\frac{1}{2}$

$\theta=\frac{\pi}{6}\ ,\ \frac{11}{6}\pi$

$\theta=\frac{\pi}{3}\ ,\ \frac{2}{3}\pi$

$\theta=\frac{\pi}{3}\ ,\ \frac{5}{3}\pi$

$\theta=\frac{2}{3}\pi\ ,\ \frac{4}{3}\pi$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\tan\theta=1$

$\theta=\frac{3}{4}\pi\ ,\ \frac{5}{4}\pi$

$\theta=\frac{3}{4}\pi\ ,\ \frac{7}{4}\pi$

$\theta=\frac{\pi}{4}\ ,\ \frac{5}{4}\pi$

$\theta=\frac{\pi}{4}\ ,\ \frac{3}{4}\pi$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\sin\theta=0$

$\theta=0$

$\theta=0\ ,\ \pi$

$\theta=\frac{\pi}{2}\ ,\ \frac{3}{2}\pi$

なし

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\cos\theta=-1$

$\theta=0$

$\theta=0\ ,\ \pi$

$\theta=\pi$

$\theta=\frac{\pi}{2}$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\sin\theta=-\frac{1}{\sqrt{2}}$

$\theta=\frac{5}{4}\pi\ ,\ \frac{7}{4}\pi$

$\theta=\frac{\pi}{4}\ ,\ \frac{3}{4}\pi$

$\theta=\frac{3}{4}\pi\ ,\ \frac{5}{4}\pi$

$\theta=\frac{\pi}{4}\ ,\ \frac{7}{4}\pi$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\cos\theta=-\frac{\sqrt{3}}{2}$

$\theta=\frac{5}{6}\pi\ ,\ \frac{7}{6}\pi$

$\theta=\frac{\pi}{6}\ ,\ \frac{11}{6}\pi$

$\theta=\frac{\pi}{6}\ ,\ \frac{5}{6}\pi$

$\theta=\frac{7}{6}\pi\ ,\ \frac{11}{6}\pi$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\tan\theta=-\sqrt{3}$

$\theta=\frac{2}{3}\pi\ ,\ \frac{5}{3}\pi$

$\theta=\frac{2}{3}\pi\ ,\ \frac{4}{3}\pi$

$\theta=\frac{\pi}{3}\ ,\ \frac{4}{3}\pi$

なし

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三角方程式①

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 sin⁡θ=12\sin\theta=\frac{1}{2}sinθ=21​

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 cos⁡θ=12\cos\theta=\frac{1}{2}cosθ=21​

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 tan⁡θ=1\tan\theta=1tanθ=1

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 sin⁡θ=0\sin\theta=0sinθ=0

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 cos⁡θ=−1\cos\theta=-1cosθ=−1

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 sin⁡θ=−12\sin\theta=-\frac{1}{\sqrt{2}}sinθ=−2​1​

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 cos⁡θ=−32\cos\theta=-\frac{\sqrt{3}}{2}cosθ=−23​​

0≤θ<2π0\le\theta<2\pi0≤θ<2π のとき、次の方程式を満たす θ\thetaθ を求めよ。 tan⁡θ=−3\tan\theta=-\sqrt{3}tanθ=−3​

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$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\sin\theta=\frac{1}{2}$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\cos\theta=\frac{1}{2}$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\tan\theta=1$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\sin\theta=0$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\cos\theta=-1$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\sin\theta=-\frac{1}{\sqrt{2}}$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\cos\theta=-\frac{\sqrt{3}}{2}$

$0\le\theta<2\pi$ のとき、
次の方程式を満たす $\theta$ を求めよ。

$\tan\theta=-\sqrt{3}$