Solving Systems by Substitution

• Infinite number of solutions

• (0, 7)

• (-5, -7)

• (5, 7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• No Solution

• (2, 2)

• (-1, 2)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (3, -6)

• (3, -8)

• Infinite number of solutions

• (3, 6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (4, -3)

• (-1, -3)

• (-4, -3)

• (-4, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (-1, 3)

• (0, -3)

• (1, 3)

• (1, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (2, -3)

• (-3, -2)

• (6, 4)

• (2, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (1, -4)

• (1, 4)

• (-4, -7)

• (-7, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system of equations. 
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step in solving a system by Substitution?

• Make sure both equations are in standard form.
• Make sure at least one equation is solved for one variable.
• Make sure both equations are in slope-intercept form.
• Make sure both equations can be solved.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -2x + 5
y = 2x - 11

• No Solution
• (0, 0)
• (3, -1)
• (4, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6