Review 3.4, Reciprocal Transf, Non-linear Inequalities

To solve, 16^5x = 64^x+7, what would be the correct set-up?

There is more than one correct answer.

• 4^4(5x)=4^16(x+7)

• 8^2(5x)=8^8(x+7)

• 4^2(5x)=4^3(x+7)

• 2^4(5x)=2^6(x+7)

Tags

CCSS.HSA.CED.A.1

Solve log(x) + log(x+3) = 1

• 5
• -2
• -5
• 2

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

Solve

• A
• B
• C
• D

Tags

CCSS.HSA.REI.A.1

• no solution
• only 6
• 6 and -2
• 3

Solve.

9(e^x) - 31 =23

• x = 1.79

• x = 4.21

• x = -3.5

• x = 1.27

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.LE.A.4

 $Solve.\ \ e^{2x}\ \ +\ 6\ =\ 7e^x$  

• x = 0
  

• x = 0 or x = 6

• x = 0 or x = ln6

• no solution

Solve for x.  Round to three decimal places, if necessary.

 $1\ =\ \frac{e^x\ -\ e^{-x}}{2}$  

• x = 0

• x = 1

• x = 0.881

• x = 2.414 or x = -0.414

Simplify:

 $\left(e^x\ +\ e^{-x}\right)^2\ +\ \left(e^x\ -\ e^{-x}\right)^2$  

hint:  use  $\left(a\pm b\right)^2\ =\ a^2\pm2ab+b^2$  

•  $2e^{2x}\ +\ 2e^{-2x}$  

•  $2e^{2x}$  

•  $2e^{2x}\ +\ 2e^{-2x}+4$  

•  $2e^{2x}\ +\ 2e^{-2x}-4$  

Identify the vertical asympotote(s) of

 $\frac{1}{x^3\ -\ 16x}$  

• x = 0

• x =  $\pm4$  

• x =0, x = $\pm4$  

• x = 0, x = 16

Consider the given graph of f(x).  If $g\ =\ \frac{1}{f\left|x\right|}$ 

Which of following is not on the graph of g?

• (0, -1)

• (1, -5/9)
  

• (-1, -5/9)

• (-1, 1/3)