Quadratic Formula

Identify the values of a, b, and c.
 $x^2+8x-3=0$  

•  $a=0,\ b=8,\ c=-3$  

•  $a=1,\ b=8,\ c=3$  

•  $a=1,\ b=8,\ c=-3$  

•  $a=0,\ b=8,\ c=3$  

Tags

CCSS.HSA.REI.B.4

What is the correct value of b in the problem?
 $x^2+6x-16$  

(a)  

Tags

CCSS.HSA.REI.B.4

Which answer shows the quadratic formula being plugged in correctly for the following problem?
 $x^2+6x-16=0$  

•  $\frac{\left(6\right)\ \frac{+}{-}\sqrt{\left(6\right)^2-4\left(1\right)\left(-16\right)}}{2\left(1\right)}$  

•  $\frac{-\left(6\right)\ \frac{+}{-}\sqrt{\left(6\right)^2-4\left(1\right)\left(16\right)}}{2\left(1\right)}$  

•  $x=\frac{-\left(6\right)\ \frac{+}{-}\sqrt{\left(6\right)^2-4\left(1\right)\left(-16\right)}}{2\left(1\right)}\$  

•  $\frac{\left(6\right)\ \frac{+}{-}\sqrt{\left(6\right)^2-4\left(1\right)\left(16\right)}}{2\left(1\right)}$  

Tags

CCSS.HSA-REI.B.4B

Mark the 2 forms of the correct use of the quadratic formula for the following problem?
 $2x^2-7x+1=0$  

•  $\frac{\left(7\right)\ \frac{+}{-}\sqrt{\left(-7\right)^2-4\left(2\right)\left(1\right)}}{2\left(2\right)}$  

•  $\frac{-\left(-7\right)\ \frac{+}{-}\sqrt{\left(-7\right)^2-4\left(2\right)\left(1\right)}}{2\left(2\right)}$  

•  $\frac{-\left(7\right)\ \frac{+}{-}\sqrt{\left(7\right)^2+4\left(2\right)\left(1\right)}}{2\left(2\right)}$  

•  $\frac{-\left(7\right)\ \frac{+}{-}\sqrt{\left(7\right)^2-4\left(2\right)\left(1\right)}}{2\left(1\right)}$  

Tags

CCSS.HSA-REI.B.4B

Identify the 'a' value: y = 16x² -8x -24

• 16
• 8
• -8
• -24

Identify the 'b' value: y = 16x² -8x -24

• 16
• -8
• 8
• -24

Identify the 'c' value: y = 16x² -8x -24

• 16
• -8
• 24
• -24

Tags

CCSS.HSA.REI.B.4

b² - 4ac would equal: y = 2x² -x -3

• 25
• -23
• -25
• 0

Tags

CCSS.HSA-REI.B.4B

Use the quadratic formula to find the solutions for

y = -x² - 5x + 12

• No Real Solution

• 
• 
• 

Tags

CCSS.HSA-REI.B.4B

Solve 2x² + 7x - 15 = 0

• -3/2 or 5

• No Solution

• -5 or 3/2

• 0.7 or 5

Tags

CCSS.HSA-REI.B.4B