1st Block Review 11/19/20

-15 = 5a +12- 2a + 6

• -11
• -3
• 10
• 7

Tags

CCSS.8.EE.C.7B

3a + 9 + 4a = 2

• -1
• 1
• no solution
• -7

Tags

CCSS.8.EE.C.7B

What is the first step in solving the equation 2a - 4(a - 5) = 10

• Add 4 to both sides
• Add the 2a and a 
• Distribute 4 to a and -5
• Distribute -4 to a and -5

Tags

CCSS.8.EE.C.7B

8 = (³⁄₄)a +12 - a + 4

• 32
• -6
• -4
• 4

Tags

CCSS.8.EE.C.7B

4(a + 3) = -32

• -11
• -44
• -20
• -8

Tags

CCSS.7.EE.B.4A

2 + 14a = -8 + 9a

• -2
• 3
• 5
• -10

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

Identify if this equation has one solution, infinitely many solutions or no solution.
-3x+1=x+9-4x

• one solution
• infinitely many
• no solution

Tags

CCSS.8.EE.C.7A

-4x + 14 ≤ 54

• x ≥ - 10
• x ≤ -10
• x ≥ 10
• x ≤ 10

Tags

CCSS.7.EE.B.4B

Solve the inequality. Don't forget to check your solution set.
12 ≥ 15 - 6y

• y ≤ ½
• y ≤ 2
• y ≥ ½
• y ≥ 2

Tags

CCSS.7.EE.B.4B

Solve:
6x+10>5x-12

• x>2
• x<2
• x<-22
• x>-22

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3