Solving Log and Natural Log Equations

log₅(4x-7)=log₅(x+5)

• 3
• 12
• 4
• 7

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSF.LE.A.4

CCSS.HSA.REI.B.3

log₂(x² - 6) = log₂(2x+2)

• 4, -2

• No Solution

• 4

• -2

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.4

CCSS.HSA.REI.B.4

log₂(x+3)=4

• 16

• 13

• 3

• 10

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

log₂(x + 2) + log₂x  = 3

• -4, 2
• -2, 4
• 2
• 1

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

Solve for x.
e^x+6 + 5 = 1

• -4.614
• -4.236
• No Solution
• -0.334

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.4

Solve:

log (x - 1) - log (x - 2) = log 5

• 7

• 4/9

• 9/4

• 1/7

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

Solve:

ln(x+8) - ln (8) = 3

• 152.68

• 188.77

• 4.24

• 8.01

Tags

CCSS.HSF.BF.B.5

Determine the correct set-up for:

log(x) + log (x-9) = 18

• log(x)/(x-9)=18

• log(-7x)=18

• log(x)+(x-9)=18

• logx(x-9)=18

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.4

Determine the correct set-up for:

log₄(x-1) - log₄(x+7) = log₄6

• log₄(x-1)/(x+7)=log₄(6)

• log₄(x-1)(x+7)=log₄(6)

• log₄(x+7)/(x-1)=log₄(6)

• (x-1)(x+7)=6

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

 $4\log_2\left(2x+24\right)-17=-9$  
Once you have isolated the log in the equation, what would be the next step?

• log both sides

• rewrite as an exponential

• nothing, you would not be able to solve it

• divide both sides by 2