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Funciones multivariables

Authored by ELIZABETH MORAN

Mathematics

University

Used 2+ times

Funciones multivariables
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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Considere la función y defina cual respuesta es correcta

 x2+y33xyx^2+y^3-3xy  

(0,0) punto silla (9/4,3/2) minimo

(0,0) maximo (9/4,3/2) minimo

(0,0) minimo (9/4,3/2) minimo

(0,0) minimo (9/4,3/2) maximo

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Considere la función y defina cual respuesta es correcta

 x2+2y2xy+12xx^2+2y^2-xy+12x  

(-48/7,-12/7) maximo

(-48/7,-12/7) minimo

(-48/7,-12/7) punto silla

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Considere la función y defina cual respuesta es correcta

 2x2+y22x2y32x^2+y^2-2x-2y-3  

(1/2,1) maximo

(1/2,1) mínimo

(1/2,1) punto silla

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Considere la función y defina cual respuesta es correcta

 2xy+4x+1y2xy+\frac{4}{x}+\frac{1}{y}  

(2,1/2) maximo

(2,1/2) mínimo

(2,1/2) punto silla

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Considere la función y defina cual respuesta es correcta

 x2y2+2lnyx^2-y^2+2\ln y  

(0,1), (0,-1) son maximos

(0,1), (0,-1) son minimos

(0,1), (0,-1) son puntos de silla

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Sea la función

 f=x+(y2)3f=x+\left(y-2\right)^3  donde  x=r+5tx=r+5t  como  y=3r4ty=3r-4t  la derivada  ft\frac{\partial f}{\partial t}  es:

 ft=512(y2)2\frac{\partial f}{\partial t}=5-12\left(y-2\right)^2  

 ft=5+12(y2)2\frac{\partial f}{\partial t}=5+12\left(y-2\right)^2  

 ft=512(y+2)2\frac{\partial f}{\partial t}=5-12\left(y+2\right)^2  

 ft=5+12(y+2)2\frac{\partial f}{\partial t}=5+12\left(y+2\right)^2  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Sea la función

 z=x+y2z=\sqrt{x+y^2}  donde  x=t2+tx=t^2+t  como  y=t200y=t-200  la derivada  zt\frac{\partial z}{\partial t}  es:

 zt=2t2+4t+12x+y2\frac{\partial z}{\partial t}=\frac{2t^2+4t+1}{2\sqrt{x+y^2}}  

 zt=2t24t+12x+y2\frac{\partial z}{\partial t}=\frac{2t^2-4t+1}{2\sqrt{x+y^2}}  

 zt=2t2+4t+12xy2\frac{\partial z}{\partial t}=\frac{2t^2+4t+1}{2\sqrt{x-y^2}}  

 zt=2t2+t+12x+y2\frac{\partial z}{\partial t}=\frac{2t^2+t+1}{2\sqrt{x+y^2}}  

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