Solve for a. c = 8 a − 3 b c=8a-3b c = 8 a − 3 b

c + 3 b 8 \frac{c+3b}{8} 8 c + 3 b

c + 3 b − 8 c+3b-8 c + 3 b − 8

c 3 b + 8 \frac{c}{3b+8} 3 b + 8 c

Algebra 1: Equations Review

Quiz

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

•

CCSS

HSA.REI.B.3, 8.EE.C.7B, HSA.REI.A.2

+4

Standards-aligned

Lauren Hall

Used 29+ times

FREE Resource

14 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$6\left(x+3\right)-\left(x+4\right)=-11$
x = _____

Tags

CCSS.8.EE.C.7B

2.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$-8\left(n-4\right)=n-40$
n = _____

Tags

CCSS.7.EE.B.4A

3.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$7\left(y-5\right)+3y=10\left(y+1\right)$
y = _____

Tags

CCSS.8.EE.C.7A

4.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$-5\left(k+2\right)=13-\left(k-1\right)$
k = _____

Tags

CCSS.8.EE.C.7B

5.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$-6-\left(2x+7\right)=-2\left(x+6\right)-1$
x = _____

Tags

CCSS.8.EE.C.7A

6.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$4\left(2x+7\right)=12-2\left(10-2x\right)$
x = _____

Tags

CCSS.8.EE.C.7B

7.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

$\frac{5}{x-3}=\frac{7}{x-9}$
x = _____

Tags

CCSS.HSA.REI.A.2

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Algebra 1: Equations Review

14 questions

$6\left(x+3\right)-\left(x+4\right)=-11$
x = _____

$-8\left(n-4\right)=n-40$
n = _____

$7\left(y-5\right)+3y=10\left(y+1\right)$
y = _____

$-5\left(k+2\right)=13-\left(k-1\right)$
k = _____

$-6-\left(2x+7\right)=-2\left(x+6\right)-1$
x = _____

$4\left(2x+7\right)=12-2\left(10-2x\right)$
x = _____

$\frac{5}{x-3}=\frac{7}{x-9}$
x = _____

$\frac{5}{6}=\frac{x-10}{3x+6}$
x = _____

$\left|x\right|=9$
x = _____

$\left|6c-3\right|=21$
c = _____

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Algebra 1: Equations Review

14 questions

6(x+3)−(x+4)=−116\left(x+3\right)-\left(x+4\right)=-116(x+3)−(x+4)=−11 x = _____

−8(n−4)=n−40-8\left(n-4\right)=n-40−8(n−4)=n−40 n = _____

7(y−5)+3y=10(y+1)7\left(y-5\right)+3y=10\left(y+1\right)7(y−5)+3y=10(y+1) y = _____

−5(k+2)=13−(k−1)-5\left(k+2\right)=13-\left(k-1\right)−5(k+2)=13−(k−1) k = _____

−6−(2x+7)=−2(x+6)−1-6-\left(2x+7\right)=-2\left(x+6\right)-1−6−(2x+7)=−2(x+6)−1 x = _____

4(2x+7)=12−2(10−2x)4\left(2x+7\right)=12-2\left(10-2x\right)4(2x+7)=12−2(10−2x) x = _____

5x−3=7x−9\frac{5}{x-3}=\frac{7}{x-9}x−35​=x−97​ x = _____

56=x−103x+6\frac{5}{6}=\frac{x-10}{3x+6}65​=3x+6x−10​ x = _____

∣x∣=9\left|x\right|=9∣x∣=9 x = _____

∣6c−3∣=21\left|6c-3\right|=21∣6c−3∣=21 c = _____

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$6\left(x+3\right)-\left(x+4\right)=-11$
x = _____

$-8\left(n-4\right)=n-40$
n = _____

$7\left(y-5\right)+3y=10\left(y+1\right)$
y = _____

$-5\left(k+2\right)=13-\left(k-1\right)$
k = _____

$-6-\left(2x+7\right)=-2\left(x+6\right)-1$
x = _____

$4\left(2x+7\right)=12-2\left(10-2x\right)$
x = _____

$\frac{5}{x-3}=\frac{7}{x-9}$
x = _____

$\frac{5}{6}=\frac{x-10}{3x+6}$
x = _____

$\left|x\right|=9$
x = _____

$\left|6c-3\right|=21$
c = _____