Assessment 7 Review

Factor by grouping
x³ - 4x² -4x + 16

• (x+4)(x+2)
• (x-4)(x² -4) 
• (x+4)(x² -4)
• (x-4)(x-2)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

What are the zeros of the polynomial function?
y = x(x - 6)(x + 5)

• 0, 6, -5
• 6, -5
• 0, -6, 5
• 1, -6, 5

Tags

CCSS.HSF-IF.C.7C

Factor: x³ + 1

• (x + 1)³

• (x+1)(x² - x + 1)

• (x - 1) (x² + x - 1)

• (x + 1)(x² - 2x + 1)

Describe the end behavior of the graph.

• x → ∞, y→ ∞ and
  x→ ∞, y→⁻∞
• x → ∞, y→ ∞ and
  x→⁻∞, y→∞
• None of these
• x →∞,y→⁻∞ and
  x→∞, y→⁻∞

Tags

CCSS.HSF-IF.C.7A

How many imaginary zeros does g(x)=x³+6x²+9x have? Hint: graph the function.

• None

• 1

• 2

• 4

What is the vertex of the equation

 $y=\left(x-3\right)^2+5$  

• (-3, 5)

• (3, 5)

• (-3, -5)

• (3, -5)

The point of intersection of the graphs of the functions k(x) and p(x) is (0,1), and k(x)=2x+1. Which of the following functions cannot be p(x)? Hint: Graph.

• -2x+1

• 3x+1

• -(3/2)x+1

• x+4

When a function, f(x), is divided by x-2, the remainder is 0, which conclusion about f(x) must be true?

• f(-2)=0

• f(2)=0

• x+2 is a factor

• No conclusion can be made

Solve for x
l 2x−1 l = 9

• x = 5 and x =-4
• x = 5 and x = -5
• Only x = 5
• No Solution

The function V(x)=4x³-40x²+100x represents the volume, in cubic centimeters, of the open top box when the corners of side length cm by cm are removed and the sides are folded up.

Find V(1.5) and V(1.75)

• V(1.5)=73.5 and V(1.75)=73.9

• V(1.5)=73.9 and V(1.75)=73.5

• V(1.5)=77.5 and V(1.75)=76.3

• V(1.5)=76.5 and V(1.75)=78.3