Bank Soal Kesetimbangan Kimia
Quiz
•
Chemistry
•
12th Grade
•
Practice Problem
•
Medium
nancy sihombing
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30 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Berikut ini adalah ciri-ciri terjadinya reaksi kesetimbangan, kecuali … .
reaksi reversibel
terjadi dalam ruang tertutup
laju reaksi ke kiri sama dengan laju reaksi ke kanan
reaksinya tidak dapat balik
tidak terjadi perubahan makroskopis
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Berikut ini faktor-faktor yang mempengaruhi pergeseran kesetimbangan,kecuali … .
konsentrasi
katalisator
suhu
tekanan
volume
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Reaksi kesetimbangan hidrolisis ester sebagai berikut.
C2H5COOCH3(aq) + H2O(l) ⇄ CH3OH(aq) + CH3COOH(aq)
Hal berikut ini memenuhi kaidah pergeseran kesetimbangan, kecuali … .
penambahan CH3OH dapat menambah C2H5COOCH3
pengambilan CH3OH dapat menambah CH3COOH
pengambilan C2H5COOCH3 dapat menambah CH3OH
penambahan air menyebabkan C2H5OH bertambah
penambahan C2H5COOCH3 dapat menambah CH3OH
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Dalam ruang tertutup terdapat reaksi kesetimbangan:
H2(g) + Cl2(g) ⇄ 2 HCl(g) ΔH = –92 kJ/mol
Jika suhu dinaikkan, maka kesetimbangan akan bergeser ke arah … .
kiri, harga K bertambah
kiri, harga K berkurang
kiri, harga K tetap
kanan, harga K bertambah
kanan, harga K tetap
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Tetapan kesetimbangan untuk reaksi:
2 SO2(g) + O2(g) ⇄ 2 SO3(g) adalah … .
K =[SO3]2 / [SO2]2 [O2]2.
K =[SO3]2 / [SO2]2 [O2]
K =[SO3 ]2 / [SO2][O2]
K =[SO2]2 [O2 ] / [SO ]
K =[SO2]2 [O2] / [SO3]2
6.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Dalam volume 5 liter terdapat 4,0 mol asam iodida, 0,5 mol yodium dan o,5 mol hidrogen dalam suatu kesetimbangan. Maka tetapan kesetimbangan untuk reaksi pembentukan asam iodida dari iodium dan hidrogen adalah … .
50
54
56
60
64
7.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Tetapan kesetimbangan untuk reaksi:
CaCO3(s) ⇄ CaO(s) + CO2(g)
adalah …
K = [CO2 ][CaO] / [CaCO3]
K =[CO2]2 [CaO]2 / [CaCO3 ]3
K = [CaCO3] / [CO2 ][CaO]
K =[CaCO3 ]2 / [CO2 ]2 [CaO]2
K = [CO2]
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