Solving Quadratics (All Methods)

What are the solutions to this quadratic?

• ±81

• ±9

• ±3

• No real solution

Tags

CCSS.HSA-REI.B.4B

Find the values for n.

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic. (Solutions)

Hint: Set each factor equal to zero, then solve.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Determine the values of

a, b, and c for

the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

What is the first step to solving THIS equation by completing the square?
a² + 10a + 21 = 0

• Set the equation equal to zero
• Divide 10 by 2 and add the result to both sides
• Add a² and 10a together
• Subtract the 21

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:

x² + 4x - 12 = 2

(x - 2)(x + 6) = 2,

by setting x -2 = 0 and x + 6 = 0.

Her solutions are x = 2 and x = -6.

Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown. She needed to set equation equal to zero.

• No, she didn't factor correctly so the rest of her work is wrong.

Tags

CCSS.HSA-REI.B.4B

Solve the following for k.

9k² = 225

• 4

• 4, -4

• 25, -25

• -5, 5

Tags

CCSS.8.EE.A.2

Solve the quadratic equation by factoring
a² + 10a + 21 = 0

• ± √21
• -3 , -7
• 3 , 7
• 28 , -7

Tags

CCSS.HSA-REI.B.4B

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

In the equation
y = x² +5x +7, match each leading coefficient with its correct letter 

• a=0, b=5, c=7
• a=1, b=5, c=7
• a=7, b=5, c=1

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.1