9.4 Problem Solving - Apply Formulas

A thin plastic cover must be placed on top of this box. How much plastic is needed?

• 525 sq cm

• 1,400 sq cm

• 21,000 sq cm

• 600 sq cm

Tags

CCSS.7.G.B.6

Representations

Emily wants to put a rosebud wallpaper border on the walls of her room. The border will form a rectangle around the room. Which formula should she use to find the length of wallpaper she needs?

• V = l × w x h

• A = l × w

• P = 4s

• P = l + l + w + w

Tags

CCSS.3.MD.D.8

Multi-Step

Spencer and Kamden are comparing the size of their suitcases. Both suitcases are shaped like rectangular prisms. Spencer's suitcase is 15 inches long, 18 inches wide, and 5 inches tall. Kamden's suitcase is 14 inches long, 15 inches wide, and 7 inches tall. Which statement is correct?

• Kamden’s suitcase can hold more because it has a greater volume.

• Kamden’s suitcase can hold more because it has a greater area.

• Spencer’s suitcase can hold more because it has a greater volume.

• Spencer’s suitcase can hold more because it has a greater area.

Tags

CCSS.5.MD.C.3

CCSS.5.MD.C.4

CCSS.5.MD.C.5

Julio’s room has a rectangular floor. He covers the floor with 180 square feet of carpet. If the width of the room is 9 feet, what is the length of the room?

• 2 feet

• 20 feet

• 58 feet

• 20 square feet

Tags

CCSS.6.EE.B.7

CCSS.6.G.A.1

Find the perimeter.

• 20 m

• 20 sq m

• 25 m

• 25 sq m

Tags

CCSS.3.MD.D.8

Find the volume.

• 72 ft

• 72 cu ft

• 24 cu ft

• 18 ft

Tags

CCSS.5.MD.C.3

CCSS.5.MD.C.4

CCSS.5.MD.C.5

CCSS.5.MD.C.6

Area = 150 sq m

Find the missing measuremnet.

Perimeter = 42 in

Find the missing measurement.

Yuan is mailing the package shown at right. He needs to find the volume of the package so he can decide what size bag of packing materials to buy to fill the package. What is the volume of the package?

Tags

CCSS.5.MD.C.3

CCSS.5.MD.C.4

CCSS.5.MD.C.5

CCSS.5.MD.C.6

A classroom floor will be covered with carpet. Which formula is needed to find the amount of carpet needed?

• P = 2l + 2w

• V = l × w × h

• A = l × w

• P = 4s

Tags

CCSS.3.MD.C.5

CCSS.3.MD.C.6

CCSS.3.MD.C.7