Solving Quadratics Review

Use the quadratic formula to solve 2x² + 2x - 12?

• -2, 3

• 2, 3

• 2, -3

• -2, -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Solve by factoring

6x² + 17x + 12 = 0

• x = -4/3, x = -3/2

• x = 9, x = 8

• x = 4, x = 3

• x = -4, x = -3

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

Solve by completing the square.

x² + 2x - 24 = 0

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

What are the solutions?

(2x-2)(5x-5) = 0

• x = -1

• x = -1 or x = 1

• x = 1

• x = 5/2, 2/5

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

Use the quadratic formula to find the solutions for

y = -x² - 5x + 12

• $\frac{-5+\sqrt{73}}{-2}and\ \frac{-5-\sqrt{73}}{-2}$

• $\frac{5+\sqrt{73}}{-2}and\ \frac{5-\sqrt{73}}{-2}$
  

• $-5+\sqrt{73}\ and\ -5-\sqrt{73}$
  

• -5 and 5

Tags

CCSS.HSA.REI.B.4

What is the discriminant?

• b²-4ac
• b²/2a
• 4ac
• b²±4ac

Tags

CCSS.HSA-REI.B.4B

How many solutions does the equation 4x² + 4x + 1 = 0 have?

• 0
• 1
• 2
• More than 2

Tags

CCSS.HSA-REI.B.4B

If the discriminant is zero you will have

• no real solutions
• two real solutions
• 1 real solution
• 1 imaginary solution

Tags

CCSS.HSA.REI.B.4

Solve using the Quadratic Formula

6x² + 12x - 1 = 0

• $\frac{-6+\sqrt{42}}{6}and\ \frac{-6-\sqrt{42}}{6}$

• $\frac{6+\sqrt{42}}{6}and\ \frac{6-\sqrt{42}}{6}$

• x = -0.08, -1.91

• x = 0.08, 1.19

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

Solve using the Quadratic Formula

6x² - 52 = 11x

• x = 4, -2.17

• x = -4, 2.17

• x = -3.71, -1.88

• x = 3.71, 1.88

Tags

CCSS.HSA-REI.B.4B