Alg 1_ Fall Semester Review 2020

3x - 5 = -26

• x=-21

• x=21

• x=-7

• x=61

Tags

CCSS.7.EE.B.4A

Solve for x:
6(2x + 1) = 18

• 3
• 17/12
• 1
• 2

Tags

CCSS.7.EE.B.4A

Solve: -7(z - 6) = -70

• 16
• -16
• 8
• -1/2

Tags

CCSS.7.EE.B.4A

What is the first step to solve this equation:
11 - 3x = 44

• Add 3 to both sides
• Subtract 11 from both sides
• Add 11 to both sides
• Divide 3 on both sides.

Tags

CCSS.7.EE.B.4A

Which operation will cancel out multiplication?

• A.  Addition
• B. Subtraction
• C. Multiplication
• D. Division

Tags

CCSS.3.OA.C.7

Solve:
2(2x + 3) = -6(x + 9)

• 1.2
• 6
• -6
• 7.5

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

What step would you take to solve this equation?

• Multiply both sides of the equation by 2
• Divide both sides of the equation by 2
• Add 2 to both sides of the equation
• Subtract 2 from both sides of the equation

Tags

CCSS.6.EE.B.7

Find the error in the problem below
19 - 2k = 3k - 1
     +3k   +3k
19 + 1k = -1
-19           -19
k = -20

• They should have divided by 1 for the last step
• They should add 19 instead of subtracting 19
• I can not find an error
• Instead of adding 3k they should subtract 3k

Tags

CCSS.HSA.REI.A.1

Solve the literal equation for the given variable.

• 2A/h
• 2/(h)
• 2Ah
• Ah/2

Tags

CCSS.HSA.CED.A.4

Solve for a.

• a = pw
• a = p/w
• a = w/p
• a = w + p

Tags

CCSS.HSA.CED.A.4