Review Linear Equations Part I

What step would you take to solve this equation?

• Multiply both sides of the equation by 2
• Divide both sides of the equation by 2
• Add 2 to both sides of the equation
• Subtract 2 from both sides of the equation

Tags

CCSS.6.EE.B.7

 $-5x\ =\ 20$  

•  $x\ =\ 4$  

•  $x\ =\ 5$  

•  $x\ =\ -4$ 

•  $x\ =\ -5$ 

Tags

CCSS.6.EE.B.7

 $-3x\ +\ 3\ =\ 12$  

•  $x\ =\ -4$  

•  $x\ =\ -3$  

•  $x\ =\ -\ 27$  

•  $x\ =\ 5$  

Tags

CCSS.7.EE.B.4A

Solve this linear equation: $\frac{1}{4}\left(4x\ +8\right)\ =10$ 

  $2x\ -\ x\ +\ 7\ =\ 20$  

•  $x\ =\ 11$  

•  $x=12$  

•  $x=13$  

Tags

CCSS.6.EE.B.7

 $-5a\ -\left(6-3a\right)=8$  

•  $a\ =\ 1$  

•  $a\ =7$  

•  $a\ =\ -1$  

•  $a\ =\ -7$  

Tags

CCSS.8.EE.C.7B

 $-8\ =-\left(x+4\right)$  

•  $x\ =\ 2$  

•  $x\ =\ -2$  

•  $x=-4$  

•  $x=4$  

Tags

CCSS.7.EE.B.4A

Solve for b:      $\frac{4b+8}{-2}=10$   

• 3

• -7

• 7

• -3

Tags

CCSS.7.EE.B.4A

Solve the equation:  $\frac{2}{3}x=-4$  

•  $x=-6$ 

•  $x=-\frac{8}{3}$  

•  $x=24$  

•  $x=-12$  

Tags

CCSS.6.EE.B.7

Solve the equation:  $x+5=-2$  

•  $x=-7$  

•  $x=3$  

•  $x=7$  

• no solution

Tags

CCSS.6.EE.B.7