Solving Equations Using Algebra

Solving Equations Using Algebra

7th - 8th Grade

10 Qs

quiz-placeholder

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Solving Equations Using Algebra

Solving Equations Using Algebra

Assessment

Quiz

Mathematics

7th - 8th Grade

Hard

Created by

Thomas Molloy

Used 4+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt


 If: 23x 4=20If:\ \frac{2}{3}x\ -4=20  

 Then: 23x4+4=204Then:\ \frac{2}{3}x-4+4=20-4  

 Then: 23x+0=24Then:\ \frac{2}{3}x+0=24  

 Then: 23x=24Then:\ \frac{2}{3}x=24  

 Then: (32)23x=(32)24Then:\ \left(\frac{3}{2}\right)\frac{2}{3}x=\left(\frac{3}{2}\right)24  

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt


 If:23x+0=24If:\frac{2}{3}x+0=24 

Then: 23x4+4=204Then:\ \frac{2}{3}x-4+4=20-4

 Then: 23x23=2423Then:\ \frac{2}{3}x-\frac{2}{3}=24-\frac{2}{3} 

 Then: 23x=24Then:\ \frac{2}{3}x=24 

Then: (32)23x=(32)24Then:\ \left(\frac{3}{2}\right)\frac{2}{3}x=\left(\frac{3}{2}\right)24

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt


 If: 23x=24If:\ \frac{2}{3}x=24 

Then: 23x4+4=204Then:\ \frac{2}{3}x-4+4=20-4

Then: 23x+0=24Then:\ \frac{2}{3}x+0=24

Then: (32)23x=(32)24Then:\ \left(\frac{3}{2}\right)\frac{2}{3}x=\left(\frac{3}{2}\right)24

 Then: 23x23=2423Then:\ \frac{2}{3}x-\frac{2}{3}=24-\frac{2}{3} 

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt


 If: (32)23x=(32)24If:\ \left(\frac{3}{2}\right)\frac{2}{3}x=\left(\frac{3}{2}\right)24 

Then: 23x4+4=204Then:\ \frac{2}{3}x-4+4=20-4

Then: 23x+0=24Then:\ \frac{2}{3}x+0=24

 Then: 23x=24Then:\ \frac{2}{3}x=24 

Then: 1x=36Then:\ 1x=36

5.

FILL IN THE BLANK QUESTION

45 sec • 1 pt


 If: 1x=36If:\ 1x=36  

 Then:Then:  

6.

OPEN ENDED QUESTION

5 mins • Ungraded

Kym switched cell phone plans. She signed up for a new plan that will save her $3.50 per month compared to her

old cell phone plan. The cost of the new phone plan for an entire year is $294. How much did Kym pay per month

under her old phone plan?

Evaluate responses using AI:

OFF

7.

FILL IN THE BLANK QUESTION

45 sec • 1 pt

Name the justification for the following statement:


 If: 12(x+9)=108If:\ 12\left(x+9\right)=-108  
 Then: (112)12(x+9)=(112)(108)Then:\ \left(\frac{1}{12}\right)12\left(x+9\right)=\left(\frac{1}{12}\right)\left(-108\right)  

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