Unit 8 Review

Solve 3³ = 3^{4x + 2}

• x = ¼
• x = -¼
• x = ½
• x = -½

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

8^3x+3 = 8⁶

• x=28
• x=3
• x=1
• x=12

Tags

CCSS.7.EE.B.4A

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8
• 4
• 2
• Cannot be determined

Tags

CCSS.8.EE.A.1

log_x1000=3

• 1

• 10

• 30

• 3

Tags

CCSS.HSF.BF.B.5

Rewrite 3⁴ = 81 in logarithmic form.

• log₃4 = 81
• log₈₁3 = 4
• log₃81 = 4
• log₄81 = 3

Tags

CCSS.HSF.BF.B.5

Rewrite log₂8 = 3 in exponential form

• 2⁸ = 3

• 2³ = 8

• 3² = 8

• 8³ = 2

Tags

CCSS.HSF.BF.B.5

Find the inverse of f(x) = -4x - 12

• f^-1(x) = 4x - 3
• f^-1(x) = -1/4x - 3
• f^-1(x) = 1/4x + 3
• f^-1(x) = -4x - 3

Tags

CCSS.HSF-BF.B.4A

The inverse has been reflected over which line?

• y = -x
• y =x
• y = 0
• y = x + 1

Tags

CCSS.HSF-BF.B.4B

Rewrite log_pt = m in exponential form.

• p^t = m
• t^m = p
• m^t = p
• p^m = t

Tags

CCSS.HSF.BF.B.5

Rewrite as a log: x = 11^y

• log₁₁(y) = x

• log_y(11) = x

• log₁₁(x) = y

• log_x(y) = 11

Tags

CCSS.HSF.BF.B.5