Activity 6-8 Test

Find the y-intercept(s) of the graph shown.

• (-3.3, 0)

• (5.6, 0)

• (-5, 0)

• (0, 4)

Tags

CCSS.HSF-IF.C.7D

What are the x-intercepts?

• 0 and 2
• -4 and 0
• 2 and 3
• 0 and 4

Tags

CCSS.HSF-IF.C.7A

What is the range of the graph?

• -2 < y < 10
• -3 < x < 3
• -2 ≤ y ≤ 10
• -3≤ x ≤ 3

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

What is the domain of the graph?

• -3 ≤ x ≤ 3
• 3 ≤ x ≤ -3
• -2 ≤ x ≤ 10
• -3 ≤ x ≤ 10

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

Which coordinate would qualify as the *absolute maximum* of this function?

• ∞

• (0, 4)

• 3

• (4, 0)

Tags

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

What is the range of the function given below?

• 0 ≤ y ≤ 7
• -2 ≤ y ≤ 4
• .2 ≤ y ≤ 4
• All real numbers

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

Identify the transformation from the graph of f(x)=x² to the graph g(x)= -(x+5)²

• shifted up five units

  reflection in x-axis

• shifted down five units

  reflection in x-axis

• shifted left 5 units

  reflection x-axis

• shifted right 5 units

  reflection x-axis

Tags

CCSS.HSF.BF.B.3

CCSS.HSG.CO.A.2

CCSS.HSG.CO.A.5

Describe the transformation of y = f(x) for the new function
 y = f(x) + 5

• The graph of y = f(x) was shifted to the right 5 units. 
• The graph of y = f(x) was shifted to the left 5 units. 
• The graph of y = f(x) was shifted up 5 units. 
• The graph of y = f(x) was shifted down 5 units.

Tags

CCSS.HSF.BF.B.3

Given f(x) = (x-3)² + 5.  What transformations took place from the original function f(x)?

• Left 3 and up 5
• Right 3 and down 5
• Left 3 and down 5
• Right 3 and up 5

Tags

CCSS.HSF.BF.B.3

CCSS.HSG.CO.A.2

If the blue graph is
f(x) = x² 
then the red must be...

• g(x) = x² - 5
• g(x) = x² + 5
• g(x) = (x - 5)²
• g(x) = (x + 5)²

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSA.REI.D.11

CCSS.HSF.BF.B.3