Identify Conic Section Equations

9th Grade - University

•

20 Qs

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Identify Conic Section Equations

Quiz

•

Mathematics

•

9th Grade - University

•

Medium

•

CCSS

HSG.GPE.A.1

Standards-aligned

Amanda Shiffer

Used 32+ times

FREE Resource

20 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{x^2}{4}-\frac{y^2}{1}=1$

line

parabola

circle

ellipse

hyperbola

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{x^2}{2}+\frac{y^2}{2}=1$

circle

hyperbola

line

parabola

ellipse

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$4\left(2-3x\right)\ =\ 5\left(y^{2\ }+3\right)$

circle

hyperbola

line

parabola

ellipse

Tags

CCSS.HSG.GPE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{y}{3}+\frac{x}{4}=1$

circle

hyperbola

line

parabola

ellipse

Tags

CCSS.HSG.GPE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$x^2=4y^{2\ }+\ 4$

circle

hyperbola

line

parabola

ellipse

Tags

CCSS.HSG.GPE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$-7=-x^2+3y^2$

circle

hyperbola

line

parabola

ellipse

Tags

CCSS.HSG.GPE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$x^2=\sqrt{5}-y^2$

circle

hyperbola

line

parabola

ellipse

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Identify Conic Section Equations

20 questions

$\frac{x^2}{4}-\frac{y^2}{1}=1$

$\frac{x^2}{2}+\frac{y^2}{2}=1$

$4\left(2-3x\right)\ =\ 5\left(y^{2\ }+3\right)$

$\frac{y}{3}+\frac{x}{4}=1$

$x^2=4y^{2\ }+\ 4$

$-7=-x^2+3y^2$

$x^2=\sqrt{5}-y^2$

$y-x=9$

$\frac{x^2}{5}=3-y^2$

$-18-x^2-\frac{y^2}{4}=-24$

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Identify Conic Section Equations

20 questions

x24−y21=1\frac{x^2}{4}-\frac{y^2}{1}=14x2​−1y2​=1

x22+y22=1\frac{x^2}{2}+\frac{y^2}{2}=12x2​+2y2​=1

4(2−3x) = 5(y2 +3)4\left(2-3x\right)\ =\ 5\left(y^{2\ }+3\right)4(2−3x) = 5(y2 +3)

y3+x4=1\frac{y}{3}+\frac{x}{4}=13y​+4x​=1

x2=4y2 + 4x^2=4y^{2\ }+\ 4x2=4y2 + 4

−7=−x2+3y2-7=-x^2+3y^2−7=−x2+3y2

x2=5−y2x^2=\sqrt{5}-y^2x2=5​−y2

y−x=9y-x=9y−x=9

x25=3−y2\frac{x^2}{5}=3-y^25x2​=3−y2

−18−x2−y24=−24-18-x^2-\frac{y^2}{4}=-24−18−x2−4y2​=−24

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$\frac{x^2}{4}-\frac{y^2}{1}=1$

$\frac{x^2}{2}+\frac{y^2}{2}=1$

$4\left(2-3x\right)\ =\ 5\left(y^{2\ }+3\right)$

$\frac{y}{3}+\frac{x}{4}=1$

$x^2=4y^{2\ }+\ 4$

$-7=-x^2+3y^2$

$x^2=\sqrt{5}-y^2$

$y-x=9$

$\frac{x^2}{5}=3-y^2$

$-18-x^2-\frac{y^2}{4}=-24$