Ch 5 Quadratic Formula, Completing the Square, Imaginary #

Ch 5 Quadratic Formula, Completing the Square, Imaginary #

9th - 10th Grade

49 Qs

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Ch 5 Quadratic Formula, Completing the Square, Imaginary #

Ch 5 Quadratic Formula, Completing the Square, Imaginary #

Assessment

Quiz

Mathematics

9th - 10th Grade

Medium

CCSS
HSA-REI.B.4B, HSN.CN.A.2, HSN.CN.A.1

+8

Standards-aligned

Created by

Tagreed Badwai

Used 7+ times

FREE Resource

49 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve the following equation by completing the square:
n2 - 2n - 3 = 0
{3 and-1}
{4 and -4}
{5 and -3}
{8 and -7}

Tags

CCSS.HSA-REI.B.4B

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which expression is a complete square (perfect square trinomial)?

x2 + 6x + ____

x2 + 6x + 9

x2 + 6x - 36

x2 + 6x + 36

x2 + 6x - 9

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Use the quadratic formula to find the solutions for

y = -x2 - 5x + 12

No Real Solution

Media Image
Media Image
Media Image

Tags

CCSS.HSA-REI.B.4B

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the first step to solving THIS equation by completing the square?
a2 + 10a + 21 = 0
Set the equation equal to zero
Divide 10 by 2 and add the result to both sides
Add a2 and 10a together
Subtract the 21

Tags

CCSS.HSA-REI.B.4B

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image
When do you use the plus or minus symbol?
±
After taking the square root of both sides
After adding the square to both sides
After taking half of b
After setting the equation equal to zero

Tags

CCSS.HSA-REI.B.4B

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve by using the Quadratic Formula

2x2 + 7x - 15 = 0

-1.5 or 5

No Solution

-5 or 1.5

0.7 or 5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the quadratic formula?

x=b(b)24(a)(c)2(a)x=\frac{b-\sqrt{\left(b\right)^2-4\left(a\right)\left(c\right)}}{2\left(a\right)}

x=(b)±(b)24(a)(c)2(a)x=\frac{-\left(b\right)\pm\sqrt{\left(b\right)^2-4\left(a\right)\left(c\right)}}{2\left(a\right)}

x=(b)±(b)24(a)(c)2ax=\frac{\left(b\right)\pm\sqrt{\left(b\right)^2-4\left(a\right)\left(c\right)}}{2a}

x=(b)±b±4(a)(c)x=-\left(b\right)\pm\sqrt{b\pm4\left(a\right)\left(c\right)}

Tags

CCSS.HSA-REI.B.4B

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