DiffEQ Practice 1

DiffEQ Practice 1

10th - 12th Grade

12 Qs

quiz-placeholder

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DiffEQ Practice 1

DiffEQ Practice 1

Assessment

Quiz

Mathematics

10th - 12th Grade

Medium

CCSS
HSS.ID.C.7, HSA.REI.A.1, HSA.CED.A.2

+1

Standards-aligned

Created by

Kathleen Keller

Used 5+ times

FREE Resource

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12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

The following Differential Equation is
 dydx=eyex\frac{\text{d}y}{\text{d}x}=\frac{e^y}{e^x}  

Separable.

Non Separable.

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find the mistake if possible:

The Diff EQ is solved correctly

Step 1 is incorrect. The separation of variables wasn't done correctly.

Step 2 is incorrect. They didn't integrate x2 correctly.

Step 3 is incorrect. They didn't take the reciprocal of x3/3+C correctly.

3.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

Of the following, which is a solution to the differential equation, select all that apply:
 y6y+8y=0y''-6y'+8y=0  

 y=2sin(4x)y=2\sin\left(4x\right)  

 y=3e2xy=3e^{2x}  

 y=Ce4x, y=Ce^{4x},\   where C is a constant

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

dy/dx = 4x/y. Suppose y(0)=1

The particular solution is

B

C

D

E

Tags

CCSS.HSA.REI.A.1

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the general solution of the differential equation y’–ysin(x)=0.

y=Cesin(x)|y|=Ce^{-\sin\left(x\right)}

y=Cesin(x)|y|=Ce^{\sin\left(x\right)}

y=Cecos(x)|y|=Ce^{-\cos\left(x\right)}

y=Cecos(x)|y|=Ce^{\cos\left(x\right)}

y=Cecos(x)|y|=-Ce^{\cos\left(x\right)}

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Which of the following is the solution to the differential equation dy/dx=(x^2)/y with initial condition y(3)=-2?

y=2e9+x33y=2e^{\frac{-9+x^3}{3}}

y=2e9+x33y=-2e^{\frac{-9+x^3}{3}}

y=2x33y=\sqrt{\frac{2x^3}{3}}

y=2x3314y=\sqrt{\frac{2x^3}{3}-14}

y=2x3314y=-\sqrt{\frac{2x^3}{3}-14}

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which of the following differential equations match the graph above?

 

 dydx=y21\frac{\text{d}y}{\text{d}x}=y^2-1  

 dydx=x21\frac{\text{d}y}{\text{d}x}=x^2-1  

 dydx=y2+1\frac{\text{d}y}{\text{d}x}=y^2+1  

 dydx=x2+1\frac{\text{d}y}{\text{d}x}=x^2+1  

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