Co/Inc/X-linked Quiz

Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.

Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the

bluest hair in the valley.

What are the possible Genotypes for the offspring?

• RR, RB, BB

• RR, RB

• BB, RB

• RB

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.

Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the

bluest hair in the valley.

What are the possible phenotypes for the offspring?

• Red, Purple, Blue

• Red, Purple

• Blue, Purple

• Purple

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.

Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the

bluest hair in the valley.

What is the probability a child would have red hair?

• 0%

• 25%

• 50%

• 75%

• 100%

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

NGSS.HS-LS3-3

Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.

Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the

bluest hair in the valley.

What is the probability a child would have Blue hair?

• 0%

• 25%

• 50%

• 75%

• 100%

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

NGSS.HS-LS3-3

Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.

Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the

bluest hair in the valley.

What is the probability a child would have Purple hair?

• 0%

• 25%

• 50%

• 75%

• 100%

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

NGSS.HS-LS3-3

In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)

Two Erminete chickens are crossed with each other. 

What is the Genotype for box #1?

• BB

• WW

• BW

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)

Two Erminete chickens are crossed with each other. 

What is the phenotype for box #4?

• Black

• White

• Erminette

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)

Two Erminete chickens are crossed with each other. 

What are the probability the offspring would be Erminete?

• 0%

• 25%

• 50%

• 75%

• 100%

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

NGSS.HS-LS3-3

In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)

Two Erminete chickens are crossed with each other. 

What are the probability the offspring would be Black?

• 0%

• 25%

• 50%

• 75%

• 100%

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-3

In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)

Two Erminete chickens are crossed with each other. 

If there were 8 offspring how many could possible be purebred?  

• 2

• 4

• 6

• 8

Tags

NGSS.HS-LS3-1

NGSS.HS-LS3-2

NGSS.HS-LS3-3