Toan 8_On tap nhan,chia da phan thuc

Toan 8_On tap nhan,chia da phan thuc

8th Grade

12 Qs

quiz-placeholder

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Toan 8_On tap nhan,chia da phan thuc

Toan 8_On tap nhan,chia da phan thuc

Assessment

Quiz

Mathematics

8th Grade

Medium

Created by

Nguyen Hien

Used 16+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Muốn nhân hai phân thức ta thực hiện

Tử nhân tử, giữ nguyên mẫu

Tử nhân tử, mẫu nhân mẫu

Phân thức 1 nhân nghịch đảo phân thức 2

Phân thức 2 nhân nghịch đảo phân thức 1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Làm tính nhân

 15x7y3\frac{15x}{7y^3}  . 2y3x2\frac{2y^3}{x^2}  

 30xy7\frac{30xy}{7}  

 307x2\frac{30}{7x^2}  

 30y7x\frac{30y}{7x}  

 307x\frac{30}{7x}  

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

 5.(x+2)4x8×x24x+8=?\frac{5.\left(x+2\right)}{4x-8}\times\frac{x-2}{4x+8}=?  


 5(x+2)4(x2)\frac{5\left(x+2\right)}{4\left(x-2\right)}  

 516\frac{5}{16}  

 x2x+2\frac{x-2}{x+2}  

 5(x2)16\frac{5\left(x-2\right)}{16}  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 x2362x+10×3x6=?\frac{x^2-36}{2x+10}\times\frac{3}{x-6}=?  

 3(x+6)2x+10\frac{3\left(x+6\right)}{2x+10}  

 x+62x+10\frac{x+6}{2x+10}  

 3(x6)2x+10\frac{3\left(x-6\right)}{2x+10}  

 3(x6)x+5\frac{3\left(x-6\right)}{x+5}  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tìm phân thức nghịch đảo của

 2y23x-\frac{2y^2}{3x}  

 2y23x\frac{2y^2}{3x}  

 3x2y2-\frac{3x}{2y^2}  

 3x2y2\frac{3x}{2y^2}  

 2x3y2\frac{2x}{3y^2}  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 5(x2)x2+7:(x2)\frac{5\left(x-2\right)}{x^2+7}:\left(x-2\right)  

 5(x2)2x2+7\frac{5\left(x-2\right)^2}{x^2+7}  

 5(x2)2\frac{5}{\left(x-2\right)^2}  

 5x2+7\frac{5}{x^2+7}  

 x2+75\frac{x^2+7}{5}  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 4x+12(x+4)2:3(x+3)x+4=?\frac{4x+12}{\left(x+4\right)^2}:\frac{3\left(x+3\right)}{x+4}=?  

 4x+4\frac{4}{x+4}  

 4(x+3)(x+4)2×x+43(x+3)=43(x+4)\frac{4\left(x+3\right)}{\left(x+4\right)^2}\times\frac{x+4}{3\left(x+3\right)}=\frac{4}{3\left(x+4\right)}  

 4(x+3)(x+4)2×x+43(x+3)=x+43(x+3)\frac{4\left(x+3\right)}{\left(x+4\right)^2}\times\frac{x+4}{3\left(x+3\right)}=\frac{x+4}{3\left(x+3\right)}  

 4(x+3)(x+4)2×x+43(x+3)=4(x+4)x+3\frac{4\left(x+3\right)}{\left(x+4\right)^2}\times\frac{x+4}{3\left(x+3\right)}=\frac{4\left(x+4\right)}{x+3}  

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