B L → = − = − \overrightarrow{BL}=_-=_- B L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − = − Usando as letras da figura completa:

A K → e E O → \overrightarrow{AK}\ e\ \overrightarrow{EO} A K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e E O <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

B G → e J O → \overrightarrow{BG}\ e\ \overrightarrow{JO} B G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e J O <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

O P → e K J → \overrightarrow{OP}\ e\ \overrightarrow{KJ} O P <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e K J <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

H G → e J F → \overrightarrow{HG}\ e\ \overrightarrow{JF} H G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e J F <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

I K → + I M → = − \overrightarrow{IK}\ +\overrightarrow{IM}=_- I K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + I M <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

I O → \overrightarrow{IO} I O <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

O I → \overrightarrow{OI} O I <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

G L → \overrightarrow{GL} G L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K M → \overrightarrow{KM} K M <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

C D → + D L → = − \overrightarrow{CD}\ +\overrightarrow{DL}=_- C D <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + D L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

C L → \overrightarrow{CL} C L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

L C → \overrightarrow{LC} L C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

O L → \overrightarrow{OL} O L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

I J → + K C → = − \overrightarrow{IJ}\ +\overrightarrow{KC}=_- I J <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + K C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

J C → \overrightarrow{JC} J C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

J G → \overrightarrow{JG} J G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K N → \overrightarrow{KN} K N <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

I C → \overrightarrow{IC} I C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A C → + C A → = − \overrightarrow{AC}+\overrightarrow{CA}=_- A C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + C A <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A C → \overrightarrow{AC} A C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

C A → \overrightarrow{CA} C A <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

− A C → -\overrightarrow{AC} − A C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

M N → + P M → = − \overrightarrow{MN}+\overrightarrow{PM}=_- M N <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + P M <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

P N → \overrightarrow{PN} P N <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

J L → \overrightarrow{JL} J L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

D G → \overrightarrow{DG} D G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A F → \overrightarrow{AF} A F <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A K → + L B → = − \overrightarrow{AK}+\overrightarrow{LB}=_- A K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + L B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K B → \overrightarrow{KB} K B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K L → \overrightarrow{KL} K L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A B → \overrightarrow{AB} A B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

Qual das seguintes afirmações é verdadeira?

Um retângulo tem quatro simetrias de reflexão.

Um triângulo tem sempre simetrias de reflexão.

Uma figura pode ter um centro de simetria, mas não ter um eixo de simetria.

Um círculo não tem simetrias de reflexão.

A figura B é imagem da figura A:

por uma rotação de 90˚ no sentido dos ponteiros do relógio e centro O.

por uma reflexão axial de eixo Ox .

por uma reflexão central de centro O.

por uma rotação de centro O e amplitude 180˚ no sentido dos ponteiros do relógio.

O número de simetrias de reflexão e o número de simetrias de rotação da figura são:

5 simetrias de reflexão e 5 simetrias de rotação.

5 simetrias de rotação e 4 simetrias de reflexão.

5 simetrias de reflexão e 4 simetrias de rotação.

4 simetrias de reflexão e 4 simetrias de rotação.

Dois vetores dizem-se colineares quando.

quando têm o mesmo comprimento.

Na figura seguinte estão representados quatro triângulos equiláteros geometricamente iguais.

O A → = C I → \overrightarrow{OA}=\overrightarrow{CI} O A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = C I <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

O A → = A G → \overrightarrow{OA}=\overrightarrow{AG} O A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = A G <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

O A → = − I G → \overrightarrow{OA}=-\overrightarrow{IG} O A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − I G <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

O A → = A M → \overrightarrow{OA\ }=\overrightarrow{AM} O A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = A M <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Na figura está representado um painel formado por quatro azulejos quadrados iguais. No painel estão representados, a amarelo, cinco quadrados geometricamente iguais e que foram numerados de 1 a 5. O quadrado 4 pode ser obtido como imagem do quadrado 1 por meio da translação associada ao vetor:

A B → + 2 C D → \overrightarrow{AB}\ +\ 2\overrightarrow{CD} A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 2 C D <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

A B → − C B → \overrightarrow{AB}\ -\overrightarrow{CB} A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − C B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

A D → + D A → \overrightarrow{AD\ }+\ \overrightarrow{DA} A D <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + D A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

1 2 A B → + C D → \frac{1}{2}\overrightarrow{AB}\ +\ \overrightarrow{CD} 2 1 A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + C D <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Na figura está representado um painel formado por quatro azulejos quadrados iguais. No painel estão representados, a amarelo, cinco quadrados geometricamente iguais e que foram numerados de 1 a 5. Qual das seguintes isometrias transforma o ponto B no ponto D ?

Rotação de centro C e amplitude 180 graus.

Translação de vetor A C → \overrightarrow{AC} A C <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Reflexão deslizante de eixo AC e vetor A C → \overrightarrow{AC} A C <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Observa a rosácea representada na figura. Qual das afirmações seguintes é a verdadeira?

A rosácea apresenta simetria de rotação, mas não simetria axial.

A rosácea apresenta simetria axial, mas não simetria de rotação.

A rosácea apresenta simetria de rotação e simetria axial.

A rosácea não apresenta qualquer tipo de simetria.

Considera o triângulo [ABC] e o vetor D E → \overrightarrow{DE} D E <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> no referencial cartesiano. Quais são as coordenada de A1, B1 e C1, sabendo que o triângulo [A1 B1C1] é a imagem do triângulo [ABC] na reflexão deslizante em relação ao eixo das ordenadas (Oy) e vetor D E → \overrightarrow{DE} D E <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ?

A1= (2, 0) ; B1 = (1, -3) e C1= (4, -2)

A1= (-2, 0 ) ; B1= (-1, -3) e C1= (-4,-2)

A1 = ( 2, 7) ; B1= (1, 4) e C1=(4, 5)

A1 =(-2,-7) ; B1= (-1,-4) e C1=( -4,-5)

A figura seguinte tem:

duas simetrias de reflexão e duas simetrias de rotação.

quatro simetrias de reflexão e duas simetrias de rotação.

uma simetria de reflexão e duas simetrias de rotação.

Vetores 8_A

Quiz

•

Mathematics

•

8th Grade

•

Practice Problem

•

Hard

•

CCSS

4.G.A.3, HSG.CO.A.4

Standards-aligned

Arlindo Chá-Chá

Used 9+ times

FREE Resource

50 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\overrightarrow{BL}=_-=_-$
Usando as letras da figura completa:

$\overrightarrow{AK}\ e\ \overrightarrow{EO}$

$\overrightarrow{BG}\ e\ \overrightarrow{JO}$

$\overrightarrow{OP}\ e\ \overrightarrow{KJ}$

$\overrightarrow{HG}\ e\ \overrightarrow{JF}$

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$A+\overrightarrow{BC}=_-$
Usando as letras da figura completa:

F

C

B

J

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\overrightarrow{IK}\ +\overrightarrow{IM}=_-$
Usando as letras da figura completa:

$\overrightarrow{OI}$

$\overrightarrow{GL}$

$\overrightarrow{IO}$

$\overrightarrow{KM}$

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\overrightarrow{CD}\ +\overrightarrow{DL}=_-$
Usando as letras da figura completa:

$\overrightarrow{CL}$

$\overrightarrow{0}$

$\overrightarrow{LC}$

$\overrightarrow{OL}$

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\overrightarrow{IJ}\ +\overrightarrow{KC}=_-$
Usando as letras da figura completa:

$\overrightarrow{JG}$

$\overrightarrow{KN}$

$\overrightarrow{IC}$

$\overrightarrow{JC}$

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$J+\overrightarrow{JL}=_-$
Usando as letras da figura completa:

G

L

J

N

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\overrightarrow{AC}+\overrightarrow{CA}=_-$
Usando as letras da figura completa

$\overrightarrow{AC}$

$\overrightarrow{CA}$

$\overrightarrow{0}$

$-\overrightarrow{AC}$

8.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\overrightarrow{MN}+\overrightarrow{PM}=_-$
Usando as letras da figura completa:

$\overrightarrow{JL}$

$\overrightarrow{PN}$

$\overrightarrow{DG}$

$\overrightarrow{AF}$

9.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\overrightarrow{AK}+\overrightarrow{LB}=_-$
Usando as letras da figura completa:

$\overrightarrow{KB}$

$\overrightarrow{KL}$

$\overrightarrow{AB}$

$\overrightarrow{0}$

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Vetores 8_A

50 questions

BL→=−=−\overrightarrow{BL}=_-=_-BL=−​=−​ Usando as letras da figura completa:

A+BC→=−A+\overrightarrow{BC}=_-A+BC=−​ Usando as letras da figura completa:

IK→ +IM→=−\overrightarrow{IK}\ +\overrightarrow{IM}=_-IK +IM=−​ Usando as letras da figura completa:

CD→ +DL→=−\overrightarrow{CD}\ +\overrightarrow{DL}=_-CD +DL=−​ Usando as letras da figura completa:

IJ→ +KC→=−\overrightarrow{IJ}\ +\overrightarrow{KC}=_-IJ +KC=−​ Usando as letras da figura completa:

J+JL→=−J+\overrightarrow{JL}=_-J+JL=−​ Usando as letras da figura completa:

AC→+CA→=−\overrightarrow{AC}+\overrightarrow{CA}=_-AC+CA=−​ Usando as letras da figura completa

MN→+PM→=−\overrightarrow{MN}+\overrightarrow{PM}=_-MN+PM=−​ Usando as letras da figura completa:

AK→+LB→=−\overrightarrow{AK}+\overrightarrow{LB}=_-AK+LB=−​ Usando as letras da figura completa:

Qual é a translação que ocorre do triângulo [ABC] para o triângulo [A'B'C'] ?

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$\overrightarrow{BL}=_-=_-$
Usando as letras da figura completa:

$A+\overrightarrow{BC}=_-$
Usando as letras da figura completa:

$\overrightarrow{IK}\ +\overrightarrow{IM}=_-$
Usando as letras da figura completa:

$\overrightarrow{CD}\ +\overrightarrow{DL}=_-$
Usando as letras da figura completa:

$\overrightarrow{IJ}\ +\overrightarrow{KC}=_-$
Usando as letras da figura completa:

$J+\overrightarrow{JL}=_-$
Usando as letras da figura completa:

$\overrightarrow{AC}+\overrightarrow{CA}=_-$
Usando as letras da figura completa

$\overrightarrow{MN}+\overrightarrow{PM}=_-$
Usando as letras da figura completa:

$\overrightarrow{AK}+\overrightarrow{LB}=_-$
Usando as letras da figura completa: