Vektor yang sama dengan ( − 5 2 ) \left(-5\ 2\right) ( − 5 2 ) adalah...

q → \overrightarrow{q} q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

p → \overrightarrow{p} p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

r → \overrightarrow{r} r <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

s → \overrightarrow{s} s <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

t → \overrightarrow{t} t <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

Jika koordinat titik P ( 3 , 7 ) \left(3,7\right) ( 3 , 7 ) dan Q ( − 2 , 5 ) \left(-2,5\right) ( − 2 , 5 ) , vektor P Q → \overrightarrow{PQ} P Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = . . .

( − 5 − 2 ) \left(-5\ -2\right) ( − 5 − 2 )

( 4 − 1 ) \left(4\ -1\right) ( 4 − 1 )

( 6 5 ) \left(6\ 5\right) ( 6 5 )

( 2 11 ) \left(2\ 11\right) ( 2 1 1 )

( − 2 − 11 ) \left(-2\ -11\right) ( − 2 − 1 1 )

Apakah yang dimaksud dengan vektor?

besaran yang mempunyai nilai dan arah

arah yang mempunyai besaran dan nilai

besaran yang tidak punya nilai dan memiliki arah

besaran yang mempunyai satuan dan arah

Vektor A: 2i-3j, dan vektor B: -4i+2j. Tentukan panjang vektor AB?

61 \sqrt{61} 6 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

36 \sqrt{36} 3 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

71 \sqrt{71} 7 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

56 \sqrt{56} 5 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

63 \sqrt{63} 6 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Jika koordinat titik P ( 3 , 7 ) \left(3,7\right) ( 3 , 7 ) dan Q ( − 2 , 5 ) \left(-2,5\right) ( − 2 , 5 ) , vektor P Q → \overrightarrow{PQ} P Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = . . .

( − 5 − 2 ) \left(-5\ -2\right) ( − 5 − 2 )

( 4 − 1 ) \left(4\ -1\right) ( 4 − 1 )

( 6 5 ) \left(6\ 5\right) ( 6 5 )

( 2 11 ) \left(2\ 11\right) ( 2 1 1 )

( − 2 − 11 ) \left(-2\ -11\right) ( − 2 − 1 1 )

Titik P(2,3) membagi ruas garis AB dengan perbandingan 5 : -2. Jika koordinat titik B(6,-9), Koordinat titik A adalah …

12 , − 27 12,-27 1 2 , − 2 7

( 27 , 12 ) \left(27,12\right) ( 2 7 , 1 2 )

( − 27 , 12 ) \left(-27,12\right) ( − 2 7 , 1 2 )

− 12 , − 27 -12,-27 − 1 2 , − 2 7

− 12 , 27 -12,27 − 1 2 , 2 7

Titik P(2, -1, 3) membagi ruas garis AB dengan perbandingan 9 : -4. Jika koordinat titik B(6,7, -9), Koordinat titik A adalah …

( 11 , 17 , − 24 ) (11,17,-24) ( 1 1 , 1 7 , − 2 4 )

( 17 , 10 , − 11 ) (17,10,-11) ( 1 7 , 1 0 , − 1 1 )

( 24 , 11 , 8 ) (24,11,8) ( 2 4 , 1 1 , 8 )

( − 12 , 8 , 17 ) (-12,8,17) ( − 1 2 , 8 , 1 7 )

( 10 , − 24 , 11 ) (10,-24,11) ( 1 0 , − 2 4 , 1 1 )

Pada segitiga ABC, diketahui A(-2, 2, -5), B (3, -8, 5) dan C(-1, -3, 0). Titik Q pada AB sehingga AQ : QB = 3 : 2. Komponen vektor (CQ) adalah ....

( 2 , − 1 , 1 ) \left(2,-1,\ 1\right) ( 2 , − 1 , 1 )

( 7 , − 5 , 5 ) (7,-5,\ 5) ( 7 , − 5 , 5 )

( 2 , − 5 , 1 ) (2,-5,1) ( 2 , − 5 , 1 )

( − 5 , 7 , 5 ) \left(-5,\ 7,\ 5\right) ( − 5 , 7 , 5 )

( 0 , 1 , 5 ) \left(0,\ 1,\ 5\right) ( 0 , 1 , 5 )

Diketahui titik A(8, -3) dan titik B(2, 3) titik P membagi ruas garis AB dengan perbandingan 2 : 1, koordinat titik P adalah ….

( 4 , 1 ) \left(4,1\right) ( 4 , 1 )

( 2 , 2 ) \left(2,2\right) ( 2 , 2 )

( 3 , 2 ) \left(3,2\right) ( 3 , 2 )

( − 4 , − 1 ) \left(-4,-1\right) ( − 4 , − 1 )

( − 4 , 1 ) \left(-4,1\right) ( − 4 , 1 )

Hasil dari ( 2 i − 5 j − 4 k ) − ( − 6 i + 3 j − 8 k ) = . . . . (2i-5j-4k)-(-6i+3j-8k)=.... ( 2 i − 5 j − 4 k ) − ( − 6 i + 3 j − 8 k ) = . . . .

8 i − 8 j + 4 k 8i-8j+4k 8 i − 8 j + 4 k

8 i − 8 j − 4 k 8i-8j-4k 8 i − 8 j − 4 k

− 4 i − 8 j − 3 k -4i-8j-3k − 4 i − 8 j − 3 k

− 4 i − 8 j − 12 k -4i-8j-12k − 4 i − 8 j − 1 2 k

− 8 i + 8 j − 4 k -8i+8j-4k − 8 i + 8 j − 4 k

Diketahui vektor a ‾ = 2 i + 5 j − 8 k \overline{a}=2i+5j-8k a = 2 i + 5 j − 8 k dan b ‾ = − 3 j + 4 k \overline{b}=-3j+4k b = − 3 j + 4 k . maka nilai dari a ‾ − 3 b ‾ = \overline{a}-3\overline{b}= a − 3 b =

2 i + 14 j − 20 k 2i+14j-20k 2 i + 1 4 j − 2 0 k

2 i − 14 j − 20 k 2i-14j-20k 2 i − 1 4 j − 2 0 k

− 2 i + 14 j − 20 k -2i+14j-20k − 2 i + 1 4 j − 2 0 k

2 i + 14 j + 20 k 2i+14j+20k 2 i + 1 4 j + 2 0 k

− 2 i − 14 j − 20 k -2i-14j-20k − 2 i − 1 4 j − 2 0 k

Diketahui vektor u ⃗ = 2 i + 3 j − 2 k u⃗=2i+3j-2k u ⃗ = 2 i + 3 j − 2 k dan vektor v ⃗ = i − 2 j + 4 k v⃗=i-2j+4k v ⃗ = i − 2 j + 4 k , hasil dari u ⃗ + v ⃗ = … u⃗+v⃗=… u ⃗ + v ⃗ = …

3 i + j + 2 k 3i+j+2k 3 i + j + 2 k

3 i − j + 2 k 3i-j+2k 3 i − j + 2 k

− 3 i + j + 2 k -3i+j+2k − 3 i + j + 2 k

3 i + 5 j + 2 k 3i+5j+2k 3 i + 5 j + 2 k

Jika vektor a ⃗ = ( 3 i + j + 2 k ) a⃗=(3i+j+2k) a ⃗ = ( 3 i + j + 2 k ) dan b → = ( − 4 i + 3 j + 5 k ) \overrightarrow{b}=(-4i+3j+5k) b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 4 i + 3 j + 5 k ) dan c → = ( 3 i − 2 j + 2 k ) \overrightarrow{c}=(3i-2j+2k) c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 i − 2 j + 2 k ) . Maka vektor a ⃗ − 2 b ⃗ + 3 c ⃗ = … a⃗-2b⃗+3c⃗=… a ⃗ − 2 b ⃗ + 3 c ⃗ = …

20 i − 11 j − 2 k 20i-11j-2k 2 0 i − 1 1 j − 2 k

20 i − 11 j + 2 k 20i-11j+2k 2 0 i − 1 1 j + 2 k

20 i − 11 j + 5 k 20i-11j+5k 2 0 i − 1 1 j + 5 k

20 i − 11 j − 4 k 20i-11j-4k 2 0 i − 1 1 j − 4 k

24 i − 11 j − 2 k 24i-11j-2k 2 4 i − 1 1 j − 2 k

Vektor A: 2i-3j, dan vektor B: -4i+2j. Tentukan panjang vektor AB?

61 \sqrt{61} 6 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

36 \sqrt{36} 3 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

71 \sqrt{71} 7 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

56 \sqrt{56} 5 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

63 \sqrt{63} 6 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

konsep vektor

12th Grade - Professional Development

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konsep vektor

Quiz

•

Mathematics

•

12th Grade - Professional Development

•

Practice Problem

•

Medium

•

CCSS

HSN-VM.B.4A, HSN-VM.B.4C, HSN-VM.B.4B

Standards-aligned

Sugiyarto Sastro Karyono

Used 13+ times

FREE Resource

30 questions

Show all answers

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Besaran berikut yang merupakan besaran vektor adalah...

panjang

massa

volume

gaya

suhu

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Vektor yang sama dengan $\left(-5\ 2\right)$ adalah...

$\overrightarrow{p}$

$\overrightarrow{q}$

$\overrightarrow{r}$

$\overrightarrow{s}$

$\overrightarrow{t}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

(i) $\overrightarrow{BA}$ = $\left(5\ 0\right)$
(ii) $\overrightarrow{AC}$ = $\left(1\ -3\right)$
(iii) $\overrightarrow{CB}$ = $\left(-4\ 3\right)$
Pernyataan yang benar adalah...

(i) saja

(ii) saja

(iii) saja

(i) dan (ii)

(ii) dan (iii)

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika koordinat titik P $\left(3,7\right)$ dan Q $\left(-2,5\right)$ , vektor $\overrightarrow{PQ}$ = . . .

$\left(-5\ -2\right)$

$\left(4\ -1\right)$

$\left(6\ 5\right)$

$\left(2\ 11\right)$

$\left(-2\ -11\right)$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui koordinat titik S $\left(4,2\right)$ dan vektor $\overrightarrow{ST}$ = $\left(-5\ 3\right)$ . Koordinat titik T adalah....

(-1, -9)

(1, 9)

(1, -9)

(-9, 1)

(9, -1)

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika koordinat titik K $\left(3,-5,11\right)$ vektor posisi titik K adalah $\overrightarrow{k}$ =. . .

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui koordinat titik M $\left(6,-1,2\right)$ dan N $\left(3,5,-7\right)$ . Vektor $\overrightarrow{NM}$ =. . .

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konsep vektor

30 questions

Besaran berikut yang merupakan besaran vektor adalah...

Vektor yang sama dengan $\left(-5\ 2\right)$ adalah...

(i) $\overrightarrow{BA}$ = $\left(5\ 0\right)$
(ii) $\overrightarrow{AC}$ = $\left(1\ -3\right)$
(iii) $\overrightarrow{CB}$ = $\left(-4\ 3\right)$
Pernyataan yang benar adalah...

Jika koordinat titik P $\left(3,7\right)$ dan Q $\left(-2,5\right)$ , vektor $\overrightarrow{PQ}$ = . . .

Diketahui koordinat titik S $\left(4,2\right)$ dan vektor $\overrightarrow{ST}$ = $\left(-5\ 3\right)$ . Koordinat titik T adalah....

Jika koordinat titik K $\left(3,-5,11\right)$ vektor posisi titik K adalah $\overrightarrow{k}$ =. . .

Diketahui koordinat titik M $\left(6,-1,2\right)$ dan N $\left(3,5,-7\right)$ . Vektor $\overrightarrow{NM}$ =. . .

Diketahui koordinat titik A $\left(-3,4\right)$ dan B $\left(2,-1\right)$ . Jika vektor posisi titik C adalah $\overrightarrow{c}$ = $\overrightarrow{AB}$ , koordinat titik C adalah. . . .

Apakah yang dimaksud dengan vektor?

Diketahui vektor $\overrightarrow{CD}$ = (-5 0 3). Jika koordinat titik D (6, 4, -1), koordinat titik C adalah . . .

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konsep vektor

30 questions

Besaran berikut yang merupakan besaran vektor adalah...

Vektor yang sama dengan (−5 2)\left(-5\ 2\right)(−5 2) adalah...

(i) BA→\overrightarrow{BA}BA = (5 0)\left(5\ 0\right)(5 0) (ii) AC→\overrightarrow{AC}AC = (1 −3)\left(1\ -3\right)(1 −3) (iii) CB→\overrightarrow{CB}CB = (−4 3)\left(-4\ 3\right)(−4 3) Pernyataan yang benar adalah...

Jika koordinat titik P (3,7)\left(3,7\right)(3,7) dan Q (−2,5)\left(-2,5\right)(−2,5) , vektor PQ→\overrightarrow{PQ}PQ​ = . . .

Diketahui koordinat titik S (4,2)\left(4,2\right)(4,2) dan vektor ST→\overrightarrow{ST}ST = (−5 3)\left(-5\ 3\right)(−5 3) . Koordinat titik T adalah....

Jika koordinat titik K (3,−5,11)\left(3,-5,11\right)(3,−5,11) vektor posisi titik K adalah k→\overrightarrow{k}k =. . .

Diketahui koordinat titik M (6,−1,2)\left(6,-1,2\right)(6,−1,2) dan N (3,5,−7)\left(3,5,-7\right)(3,5,−7) . Vektor NM→\overrightarrow{NM}NM =. . .

Diketahui koordinat titik A (−3,4)\left(-3,4\right)(−3,4) dan B (2,−1)\left(2,-1\right)(2,−1) . Jika vektor posisi titik C adalah c→\overrightarrow{c}c = AB→\overrightarrow{AB}AB , koordinat titik C adalah. . . .

Apakah yang dimaksud dengan vektor?

Diketahui vektor CD→\overrightarrow{CD}CD = (-5 0 3). Jika koordinat titik D (6, 4, -1), koordinat titik C adalah . . .

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Popular Resources on Wayground

Discover more resources for Mathematics

Vektor yang sama dengan $\left(-5\ 2\right)$ adalah...

(i) $\overrightarrow{BA}$ = $\left(5\ 0\right)$
(ii) $\overrightarrow{AC}$ = $\left(1\ -3\right)$
(iii) $\overrightarrow{CB}$ = $\left(-4\ 3\right)$
Pernyataan yang benar adalah...

Jika koordinat titik P $\left(3,7\right)$ dan Q $\left(-2,5\right)$ , vektor $\overrightarrow{PQ}$ = . . .

Diketahui koordinat titik S $\left(4,2\right)$ dan vektor $\overrightarrow{ST}$ = $\left(-5\ 3\right)$ . Koordinat titik T adalah....

Jika koordinat titik K $\left(3,-5,11\right)$ vektor posisi titik K adalah $\overrightarrow{k}$ =. . .

Diketahui koordinat titik M $\left(6,-1,2\right)$ dan N $\left(3,5,-7\right)$ . Vektor $\overrightarrow{NM}$ =. . .

Diketahui koordinat titik A $\left(-3,4\right)$ dan B $\left(2,-1\right)$ . Jika vektor posisi titik C adalah $\overrightarrow{c}$ = $\overrightarrow{AB}$ , koordinat titik C adalah. . . .

Diketahui vektor $\overrightarrow{CD}$ = (-5 0 3). Jika koordinat titik D (6, 4, -1), koordinat titik C adalah . . .