Equations of Circles Completing the Square

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)
• (4, 3)
• (-4, -3)
• (3, 4)

Tags

CCSS.HSG.GPE.A.1

Complete the square for

x² - 12x + ____

• 
  

  $12^2$

• $6^2$
  

• $-6^2$
  

• 24

Complete the square.

x² + 6x + ____

• $3^2$

• $6^2$
  

• $12$
  

• $-3^2$
  

Given the perfect square trinomial, identify the equivalent expression

 $x^2-18x+81$  

• (x-18)²

• (x-9)²

• (x+81)²

• (x+9)²

Determine the equation of the circle in standard form: 

 $x^2+y^2+6x-12y+20=0$  

• (x-3)² + (y+6)² = 25

• (x+3)² + (y-6)² = 25

• (x-3)² + (y+6)² = 45

• (x+3)² + (y-6)² = 5

Determine the equation of the circle in standard form:

 $x^2+y^2+4x+6y-36=0$  

• (x+2)² + (y+3)² = 49

• (x+2)² + (y+3)² = 13

• (x-2)² + (y-3)² = 49

• (x-2)² + (y-3)² = 13

A circle has the equation  $x^2+y^2-12x+8y=-3$    Use completing the square to write the equation in standard form.

• (x - 6)² + (y + 4)² = 49

• (x + 4)² + (y - 6)² = 49

• (x - 6)² + (y + 4)² = 55

• x² + y² = 55

 $x^2+12y+y^2-4x=8$  

Change the equation to standard form

• (x+2)²+(y-6)²=48

• (x-2)²+(y+6)²=48

• (x-6)²+(y-2)²=48

• (x+2)²+(y-6)²=48

Find the center and radius of the circle: 

 $y^2+14x-2y=-1-x^2$  

• center= -7,2 radius= 3

• center= -7,1 radius= 7

• center= -4,1 radius= 5