Constructing Linear Equations

find the slope using these two points: (24,6) (4,2)

• 
  

  $\frac{1}{5}$
  

• 5

• $-\frac{1}{5}$

• -5

Tags

CCSS.8.EE.B.5

Find the equation using the table

• y= -4x-5

• y-4x=5

• y=-4x+5

Tags

CCSS.8.F.A.1

CCSS.8.F.B.4

Bob has $150 in his savings account and saves $40 per month. Which equation represents the amount Bob has in his account after x months?

• y = 150 + 40

• y = 40x + 150

• y = 150x + 40

Tags

CCSS.HSF-BF.A.1A

Construct a linear model for the graph.

•  $y=-\frac{1}{2}x-2$  

•  $y=-2x-2$  
  

•  $y=\frac{1}{2}x-2$  

•  $y=-\frac{1}{2}x-4$  

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

Construct a linear model for the table.

• $y=8x+2$

• $y=6x+0$

• $y=6x+2$

• $y=6x+1$

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

A factory produces 25 cars each day.  There are already 20 that have been completed.  Construct a linear model to represent the number of cars in the factory.

• $y=20x+25$

• $y=25x+20$

• $y=-25x+20$

• $y=25x-20$

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

The slope of a line is 5 and passes through the point (2, -3).

If you are trying to find the y-intercept, what variable will be replaced with the number 2 in y = mx + b ?

• y

• m

• x

• b

What is the rate of change for this point?

• $-\frac{1}{2}$

• $2$

• $\frac{1}{2}$

• $-2$

Tags

CCSS.HSF-LE.A.1B

A linear function will....

• ... have a constant rate of change and be a curved line

• ... have a constant rate of change and be a straight line.

• ... not pass the vertical line test

• ... graph as a curved line

Answer explanation

linear = constant rate of change = straight line

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

CCSS.8.F.B.4

Where do you find the initial value on a graph?

• Where the graph touches the y-axis (x=0)

• Where the graph touches the x-axis (y=0)

• At the Origin

Answer explanation

The initial value is the y-value when x=0, so look at the y-axis.

Tags

CCSS.8.F.B.4

CCSS.8.SP.A.3