La suma de los vectores A → = ( 0 , 1 , 1 ) , B → = ( 3 , 0 , 0 ) \overrightarrow{A}=\ \left(0,1,1\right)\ \ ,\ \overrightarrow{B}=\ \left(3,0,0\right) A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 0 , 1 , 1 ) , B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , 0 , 0 ) es =

( 3 , 1 , 1 ) \left(3,1,1\right) ( 3 , 1 , 1 )

( 0 , 1 , 1 ) \left(0,1,1\right) ( 0 , 1 , 1 )

( 3 , 0 , 1 ) \left(3,0,1\right) ( 3 , 0 , 1 )

( − 3 , 1 , 1 ) \left(-3,1,1\right) ( − 3 , 1 , 1 )

Las coordenadas de los vectores A → y B → \overrightarrow{A}\ y\ \overrightarrow{B} A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> y B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> conforme el dibujo son:

A → = ( 2 , 2 ) , B → = ( − 3 , 2 ) \overrightarrow{A}=\left(2,2\right),\ \overrightarrow{B}=\left(-3,2\right) A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 2 , 2 ) , B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 3 , 2 )

A → = ( 3 , 2 ) , B → = ( − 3 , 2 ) \overrightarrow{A}=\left(3,2\right)\ ,\ \overrightarrow{B}=\left(-3,2\right) A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , 2 ) , B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 3 , 2 )

A → = ( 3 , 3 ) , B → = ( 3 , 3 ) \overrightarrow{A}=\left(3,3\right)\ ,\ \overrightarrow{B}=\left(3,3\right) A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , 3 ) , B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , 3 )

A → = ( 2 , 2 ) , B → = ( 3 , 2 ) \overrightarrow{A}=\left(2,2\right)\ ,\ \overrightarrow{B}=\left(3,2\right) A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 2 , 2 ) , B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 , 2 )

El resultado de ∫ x y x d y \int_x^y\text{ }\sqrt{x}dy ∫ x y x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> d y

x ( y − x ) \sqrt{x}\left(y-x\right) x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( y − x )

y \sqrt{y} y <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− x -\sqrt{x} − x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

x \sqrt{x} x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Si N es el conjunto de los números naturales y C el conjunto de los números complejos, la relación correcta se expresa como

N ⊄ C N\not\subset C N  ⊂ C

Diagnostico

Authored by Dr. Elivar

Physics

University

Used 35+ times

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

16 questions

Show all answers

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Una función de tipo
$\frac{1}{x^2}$ es :

Creciente

Decreciente

Lineal

Constante

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

El valor absoluto de
$\left|-35\right|$ es:

-35

-35/35

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

La suma de los vectores
$\overrightarrow{A}=\ \left(0,1,1\right)\ \ ,\ \overrightarrow{B}=\ \left(3,0,0\right)$ es =

$\left(0,1,1\right)$

$\left(3,0,1\right)$

$\left(-3,1,1\right)$

$\left(3,1,1\right)$

FILL IN THE BLANK QUESTION

20 sec • 1 pt

El producto vectorial cruz de los vectores mostrados es (número):

FILL IN THE BLANK QUESTION

30 sec • 1 pt

El producto vectorial punto de los vectores mostrados es (número)
$\overrightarrow{A}=\left(1,1\right)\ \circ\ \overrightarrow{B}=\left(-1,1\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Las coordenadas de los vectores
$\overrightarrow{A}\ y\ \overrightarrow{B}$ conforme el dibujo son:

$\overrightarrow{A}=\left(3,2\right)\ ,\ \overrightarrow{B}=\left(-3,2\right)$

$\overrightarrow{A}=\left(3,3\right)\ ,\ \overrightarrow{B}=\left(3,3\right)$

$\overrightarrow{A}=\left(2,2\right)\ ,\ \overrightarrow{B}=\left(3,2\right)$

$\overrightarrow{A}=\left(2,2\right),\ \overrightarrow{B}=\left(-3,2\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{\text{d}\frac{-1}{x2}}{\text{d}y}$ El resultado es:

$\frac{-2}{x^3}$

$0$

$\frac{2}{x^2}$

$\frac{2}{x^3}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

El resultado de $\int_x^y\text{ }\sqrt{x}dy$

$\sqrt{y}$

$-\sqrt{x}$

$\sqrt{x}$

$\sqrt{x}\left(y-x\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

El resultado de $\lim_{x\rightarrow0}\ \frac{x^3}{x^2}$

-1

10.

FILL IN THE BLANK QUESTION

20 sec • 1 pt

¿ Es cierta la relación $\left|\frac{-1}{x}\right|\equiv\frac{1}{x}$ ? Escribe V para verdadero y F para falso.

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

20 questions

DP014_Pre-UPS3@1: Ch5 & Ch6

Quiz

•

University

15 questions

SAMTK Day 2

Quiz

•

University

20 questions

2021 GENAP PTS FISIKA X TIPTL,TAV,TKR,TBSM

Quiz

•

11th Grade - Professi...

20 questions

LATIHAS SOAL FISIKA LISTRIK DC & LISTRIK STATISXII

Quiz

•

University

20 questions

Ôn Tập KTCKI. Vật Lý 10

Quiz

•

10th Grade - University

17 questions

Νόμος του Gauss

Quiz

•

University

18 questions

Linear Motion / Gerakan Linear (F4)

Quiz

•

KG - Professional Dev...

20 questions

Energias renovables by cuarto

Quiz

•

University

Popular Resources on Wayground

15 questions

Fractions on a Number Line

Quiz

•

3rd Grade

20 questions

Equivalent Fractions

Quiz

•

3rd Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

54 questions

Analyzing Line Graphs & Tables

Quiz

•

4th Grade

$fractions$

22 questions

fractions

Quiz

•

3rd Grade

20 questions

Main Idea and Details

Quiz

•

5th Grade

20 questions

Context Clues

Quiz

•

6th Grade

15 questions

Equivalent Fractions

Quiz

•

4th Grade

Discover more resources for Physics

7 questions

How James Brown Invented Funk

Interactive video

•

10th Grade - University

5 questions

Helping Build the Internet: Valerie Thomas | Great Minds

Interactive video

•

11th Grade - University

12 questions

IREAD Week 4 - Review

Quiz

•

3rd Grade - University

23 questions

Subject Verb Agreement

Quiz

•

9th Grade - University

7 questions

Renewable and Nonrenewable Resources

Interactive video

•

4th Grade - University

19 questions

Review2-TEACHER

Quiz

•

University

15 questions

Pre2_STUDENT

Quiz

•

University

20 questions

Ch. 7 Quadrilateral Quiz Review

Quiz

•

KG - University

Diagnostico

Una función de tipo 1x2\frac{1}{x^2}x21​ es :

El valor absoluto de ∣−35∣\left|-35\right|∣−35∣ es:

La suma de los vectores A→= (0,1,1) , B→= (3,0,0)\overrightarrow{A}=\ \left(0,1,1\right)\ \ ,\ \overrightarrow{B}=\ \left(3,0,0\right)A= (0,1,1) , B= (3,0,0) es =

El producto vectorial cruz de los vectores mostrados es (número):

El producto vectorial punto de los vectores mostrados es (número) A→=(1,1) ∘ B→=(−1,1)\overrightarrow{A}=\left(1,1\right)\ \circ\ \overrightarrow{B}=\left(-1,1\right)A=(1,1) ∘ B=(−1,1)

Las coordenadas de los vectores A→ y B→\overrightarrow{A}\ y\ \overrightarrow{B}A y B conforme el dibujo son:

d−1x2dy\frac{\text{d}\frac{-1}{x2}}{\text{d}y}dydx2−1​​ El resultado es:

El resultado de ∫xy xdy\int_x^y\text{ }\sqrt{x}dy∫xy​ x​dy

El resultado de lim⁡x→0 x3x2\lim_{x\rightarrow0}\ \frac{x^3}{x^2}x→0lim​ x2x3​

¿ Es cierta la relación ∣−1x∣≡1x\left|\frac{-1}{x}\right|\equiv\frac{1}{x}∣∣∣∣​x−1​∣∣∣∣​≡x1​ ? Escribe V para verdadero y F para falso.

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Physics

Una función de tipo
$\frac{1}{x^2}$ es :

El valor absoluto de
$\left|-35\right|$ es:

La suma de los vectores
$\overrightarrow{A}=\ \left(0,1,1\right)\ \ ,\ \overrightarrow{B}=\ \left(3,0,0\right)$ es =

El producto vectorial punto de los vectores mostrados es (número)
$\overrightarrow{A}=\left(1,1\right)\ \circ\ \overrightarrow{B}=\left(-1,1\right)$

Las coordenadas de los vectores
$\overrightarrow{A}\ y\ \overrightarrow{B}$ conforme el dibujo son:

$\frac{\text{d}\frac{-1}{x2}}{\text{d}y}$ El resultado es:

El resultado de $\int_x^y\text{ }\sqrt{x}dy$

El resultado de $\lim_{x\rightarrow0}\ \frac{x^3}{x^2}$

¿ Es cierta la relación $\left|\frac{-1}{x}\right|\equiv\frac{1}{x}$ ? Escribe V para verdadero y F para falso.