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Toan 8_ On tap giai phuong tình (tiep)

Authored by Nguyen Hien

Mathematics

8th Grade

Used 26+ times

Toan 8_ On tap giai phuong tình (tiep)
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Giải phương trình

 x+4=2x5x+4=2x-5  

 S={1}S=\left\{-1\right\}  

 S={1}S=\left\{1\right\}  

 S={9}S=\left\{9\right\}  

 S={2}S=\left\{-2\right\}  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Nghiệm của phương trình

 x2+x3=56\frac{x}{2}+\frac{x}{3}=\frac{5}{6}  là:

 x=1x=-1  

 x=1x=1  

 x=2x=2  

 x=2x=-2  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tập nghiệm của phương trình

 7+2x=223x7+2x=22-3x  là:

 x=3x=3  

 x=3x=-3  

 S={3}S=\left\{3\right\}  

 S={3}S=\left\{-3\right\}  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 x3+2x14=56\frac{x}{3}+\frac{2x-1}{4}=\frac{5}{6}  
Chọn dòng quy đồng đúng nhất

 2x6+3(2x1)12=1012\Longleftrightarrow\frac{2x}{6}+\frac{3\left(2x-1\right)}{12}=\frac{10}{12}  

 4x12+3(2x1)12=1012\Longleftrightarrow\frac{4x}{12}+\frac{3\left(2x-1\right)}{12}=\frac{10}{12}  

 4x123(2x1)12=1012\Longleftrightarrow\frac{4x}{12}-\frac{3\left(2x-1\right)}{12}=\frac{10}{12}  

 12x123(2x1)12=1012\Longleftrightarrow\frac{12x}{12}-\frac{3\left(2x-1\right)}{12}=\frac{10}{12}  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 (x1)(2x1)=9x\left(x-1\right)-\left(2x-1\right)=9-x  

 x12x1=9x\Longleftrightarrow x-1-2x-1=9-x  

 x12x+1=x9\Longleftrightarrow x-1-2x+1=x-9  

 x+12x1=9x\Longleftrightarrow x+1-2x-1=9-x  

 x+12x+1=9x\Longleftrightarrow-x+1-2x+1=9-x  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 2+x5x=12x4\frac{2+x}{5}-x=\frac{1-2x}{4}   
Sau khi quy đồng, khử mẫu ta được 

 4(2+x)x=5(12x)4\left(2+x\right)-x=5\left(1-2x\right)  

 4(2+x)5x=5(12x)4\left(2+x\right)-5x=5\left(1-2x\right)  

 4(2+x)20x=5(12x)4\left(2+x\right)-20x=5\left(1-2x\right)  

 (2+x)x=12x\left(2+x\right)-x=1-2x  

7.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Phương trình tích là phương trình có dạng :

A(x)+B(x)=0A\left(x\right)+B\left(x\right)=0

A(x)B(x)=0A\left(x\right)-B\left(x\right)=0

A(x)B(x)=0\frac{A\left(x\right)}{B\left(x\right)}=0

A(x).B(x)=0A\left(x\right).B\left(x\right)=0

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