Unit 4B Quizizz Review

 $Let\ f\left(x\right)=-4x+10\ and\ g\left(x\right)=5x-13.\$  
 $Find\ f\left(g\left(2\right)\right).$  

 $Given\ f\left(x\right)=4x\ and\ g\left(x\right)=\frac{1}{x-4}\ \ ,\$  find the restriction on the domain of  $g\left(f\left(x\right)\right).$   (x cannot equal what number?)

Given f = {(1,2) (3,4) (5,6)}

What is the inverse?

• $f^{-1}=\left\{\left(-1,-2\right)\ \left(-3,-4\right)\ \left(-5,-6\right)\right\}$

• $f^{-1}=\left\{\left(2,1\right)\ \left(4,3\right)\ \left(6,5\right)\right\}$

• $f^{-1}=\left\{\left(-2,-1\right)\ \left(-4,-3\right)\ \left(-6,-5\right)\right\}$

Find the inverse of the graph shown here.

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Which of the following functions is the inverse of  $f\left(x\right)=\frac{7}{3}x-2\ \ ?$  

•  $f^{-1}\left(x\right)=\frac{3}{7}x+2$  

•  $f^{-1}\left(x\right)=-\frac{7}{3}x+\frac{6}{7}$  

•  $f^{-1}\left(x\right)=\frac{3}{7}x+\frac{6}{7}$  

•  $f^{-1}\left(x\right)=-\frac{7}{3}x+2$  

Look at the graph of the function. Determine if the inverse of the given function is also a function and explain why.

• The inverse is a function because the original function passes the vertical line test.

• The inverse is a function because the original function passes the horizontal line test.

• The inverse is not a function because the original function fails the vertical line test.

• The inverse is not a function because the original function fails the horizontal line test.

Look at the graph of the function. Determine if the inverse of the given function is also a function and explain why.

• The inverse is a function because the original function passes the vertical line test.

• The inverse is a function because the original function passes the horizontal line test.

• The inverse is not a function because the original function fails the vertical line test.

• The inverse is not a function because the original function fails the horizontal line test.