SOR 10 class

Fe(s) + Cl2(g) → FeCl3(s) in the reaction reducing agent would be...

• Fe

• Cl2

• FeCl3

• Fe2+

How many liters of fluorine is needed to produce 4.48 liters of O2?

2F2(g) + 2H2O(l) → 4HF(g) + O2(g)

• 11.2

• 4.48

• 8.96

• 22.4

F2(g) + 2NaCl(aq) → 2NaF(aq) + Cl2(g) oxidising agent is

• F2

• Cl

• Cl2

• NaCl

HCl(g) + MnO2(s) → MnCl2(aq) + H2O(l) + Cl2(g) sum of coefficients

• 11

• 9

• 10

• 8

2NaIO3(aq) + 12HCl(conc) → I2(s) + 5Cl2(g) + 2NaCl(aq) + 6H2O(l) oxidising agent is

• H2O

• I2

• HCL

• NaIO3

During electrolysis (with an inert anode), a solution of copper (II) nitrate (Cu (NO3) 2) 9.6 g of metal was released at the cathode. Calculate the volume of gas (n.v.) evolved at the anode

• 1.32

• 0.64

• 1.68

• 2.45

Conducted electrolysis of an aqueous solution of silver nitrate with an inert anode. The mass of silver reduced at the cathode was found to be 2.16 g. What volume of gas (n.u.) was released at the anode?

• 11.2

• 0.112 l

• 22.4

• 5.6

Br2(l) + H2S(g) → HBr(g) + S(g) sum of coefficients

• 5

• 6

• 7

• 4

CuBr2 during electrolysis of solution

• cathode Cu anode Br2

• cathode H2 anode Br2

• cathode Cu anode O2

• cathode O2 anode Br2

during electrolysis of solution of K2SO4

• cathode K anode SO2

• cathode H2 anode SO2

• cathode H2 anode O2

• cathode K anode O2