Factoring Trinomials by Grouping Intro

To factor a trinomial by grouping, start by...

• multiplying the "a" term times the "c" term and identifying the "b" term

• saying a quick prayer

• multiplying the "b" term times the "c" term and identifying the "a" term

• multiplying the "x" term times the "y" term and identifying the "m" term

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

When factoring trinomials by grouping, after you multiply the "a" and the "c" term and identify the "b" term, use these 2 values as clues to find:

• 2 numbers that subtract to "a" times "c" and add to "b"

• 2 numbers that divide to "a" times "c" and add to "b"

• 2 numbers that sum to "a" times "c" and subtract to "b"

• 2 numbers that multiply to "a" times "c" and add to "b"

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

To factor the trinomial 6x² + 11x +3, start by multiplying "a" times "c" and identifying "b". Use ax² + bx + c to find these values.

• true

• false

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

In the trinomial  $6x^2+11x+3$   ...

•  $a\cdot c\ =6\cdot3\ =18\$  and  $b\ =\ 11$  

•  $a\cdot c=\ 6\cdot11=66$  and b = 3
  

•   $a\ \cdot c=11\cdot3\ =\ 33\ and\ b=6$  

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

To factor the trinomial  $6x^2+11x+3$   ...

• you need to find 2 numbers that multiply to 3 and add to 66

• you need to find 2 numbers that multiply to 18 and subtract to 11

•  you need to find 2 numbers that multiply to 18 and add to 11

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

To factor the trinomial  $6x^2+11x+3$  , find 2 numbers that multiply to 18 and add to 11. Those two numbers are:

• 9 and -2

• 9 and 2

• -9 and -2

• -9 and 2

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

To factor the trinomial  $6x^2+11x+3$  ,  write the bx term, which is the 11x , using 2 terms like this:

•  $6x^2+9x+2x+3$  and then continue factoring by grouping

•  $6x^2-9x\ -2x+3$  and then continue factoring by grouping. 

•  $6x^2+10x+x+3$  and then continue factoring by grouping. 

•  $6x^2+9x-2x+3$  and then continue factoring by grouping. 

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

To factor 3x² + 14x + 8, find the 2 clue numbers first. The clue numbers are:

• a⋅c =11 and b=14

• a⋅c =14 and b=3

• a⋅c =42 and b=8

• a⋅c =24 and b=14

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

To factor 3x² + 14x + 8, find the 2 clue numbers first. Then, use the clue numbers to find the 2 numbers we will use for "bx".

• the 2 numbers that multiply to 24 and add to 14 are 6 and 4.

• the 2 numbers that multiply to 24 and add to 14 are 24 don't exist.

• the 2 numbers that multiply to 24 and add to 14 are 2 and 12.

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

To factor 3x² + 14x + 8, write the middle term using the 2 numbers that multiply to 24 and add to 12, make sure to include the "x". Write it like this:

• 3x² + 13x +x + 8

• 3x² + 12x +2x + 8

• 3x² + 6x +4x + 8

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3