Unit 7 Pre- Test / Post- Test

Is the following exponential function growth or decay?

 $y=6\left(\frac{1}{3}\right)^x$  

• Growth,  $6$ 
  

• Growth,  $\frac{1}{3}$ 
  

• Decay,  $6$  
  

• Decay,  $\frac{1}{3}$  
  

Tags

CCSS.HSF-IF.C.8B

Given the parent function  $y=2^x$ 

Write a function for the transformations indicated below:
Reflection over the x-axis, Shift 5 units left, Translated 3 units up

•  $y=-2^{x+5}+3$  

•  $y=-2^{x+3}+5$  

•  $y=2^{-x+5}+3$  

•  $y=2^{-x+3}+5$  

Rewrite the given equation in logarithmic form
 $64^{\frac{1}{2}}=8$  

•  $\log_8\left(\frac{1}{2}\right)=64$  

•  $\log_864=\frac{1}{2}$  

•  $\log_{64}8=\frac{1}{2}$  

•  $\log_{64}\left(\frac{1}{2}\right)=8$  

Tags

CCSS.HSF.BF.B.5

Evaluate the expression below.
 $\log_5\left(\frac{1}{125}\right)$  

•  $x=-3$  

•  $x=3$  

•  $x=25$  

•  $x=\frac{1}{3}$  

To determine the exponential growth or decay, which formula would you use?

•  $A=Pe^{rt}$  

•  $A=P\left(1\pm r\right)^t$  

•  $A=lw$  

•  $A=\frac{1}{2\ }h\left(b_1+b_2\right)$  

To determine the final value given compound interest, which formula would you use?

•  $A=Pe^{rt}$ 

•  $A=P\left(1\pm r\right)^t$  

• $A=lw$

•  $A=\frac{1}{2\ }h\left(b_1+b_2\right)$ 

A computer valued at $6,400 depreciates at a rate of 12.8% per year. Write a function that models the value of the computer after 5 years.

• $A=6400\left(.125\right)^5$

• $A=6400\left(.872\right)^5$

• $A=6400\left(12.8\right)^5$

• $A=6400\left(1.128\right)^5$

Find the amount in a continuously compounded account for the following condition.

Principal, $6,000

Annual Interest Rate, 4.6%

Time 5 years

• 31,412.25

• 8,252.17

• 6,282.45

• 7,551.60

Expand the given logarithm.
 $\log\left(\frac{2^3}{6}\right)$ 

•  $3\log2-\log6$  

•  $\log2^3-\log6$  

•  $2\ \log3-\log6$  

•  $\log8-\log6$  

Condense the given expression to a single logarithm.
 $5\log_7y+5\log_7z$  

•  $\log_75yz$  

•  $5\log_7yz$  

•  $\log_7\left(\frac{y^5}{z^5}\right)$  

•  $\log_7\left(yz\right)^5$