Midpoint and Distance Formula

Midpoint and Distance Formula

9th - 12th Grade

10 Qs

quiz-placeholder

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Distance Formula

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Midpoint and Distance Formula

Midpoint and Distance Formula

Assessment

Quiz

Mathematics

9th - 12th Grade

Medium

Created by

Mr Kershaw

Used 33+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the following is the correct midpoint formula given two endpoints (x1, y1) and (x2, y2)?

(x1+x22,y1+y22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)

(x1x22,y1y22)\left(\frac{x_1-x_2}{2},\frac{y_1-y_2}{2}\right)

(x1+y12,x2+y22)\left(\frac{x_1+y_1}{2},\frac{x_2+y_2}{2}\right)

(x2x12,y2y12)\left(\frac{x_2-x_1}{2},\frac{y_2-y_1}{2}\right)

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given two points (x1, y1), (x2, y2) the distance between them is:

d=(x1+y1)2(x2+y2)2d=\sqrt{\left(x_1+y_1\right)^2-\left(x_2+y_2\right)^2}

d=(x1y1)2(x2y2)2d=\sqrt{\left(x_1-y_1\right)^2-\left(x_2-y_2\right)^2}

d=(x1+x2)2(y1+y2)2d=\sqrt{\left(x_1+x_2\right)^2-\left(y_1+y_2\right)^2}

d=(x1x2)2+(y1y2)2d=\sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the MIDPOINT of the segment?

(3,4)\left(-3,4\right)

(5,4)\left(5,4\right)

(1,4)\left(1,4\right)

(4,1)\left(4,1\right)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the HORIZONTAL distance between the two points?

-3

8

4

5

9

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the MIDPOINT of the segment?

(2,7)\left(2,7\right)

(2,5)\left(2,-5\right)

(1,2)\left(1,2\right)

(2,1)\left(2,1\right)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the VERTICAL distance between the two points?

12

6

7

2

13

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Using the Midpoint Formula, which is the correct setup to find the MIDPOINT for the endpoints:


 (4, 3) and (2, 7)

 (x1+x22,y1+y22)=(4+22,3+72)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)=\left(\frac{4+2}{2},\frac{3+7}{2}\right)  

 (x1+x22,y1+y22)=(4+32,2+72)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)=\left(\frac{4+3}{2},\frac{2+7}{2}\right)  

 (x1+x22,y1+y22)=(3+72,4+22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)=\left(\frac{3+7}{2},\frac{4+2}{2}\right)  

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