Precalc - 5.3 Cramer's Rule w/ 2 Equations

• there is no difference

• A

• B

• C

• D

What is the formula for the determinant of a 2x2 matrix?

• ad-bc

• ab-cd

• ad+bc

• (a+d)(b+c)

• A
• B
• C
• D

• A

• B

• C

• D

When setting up Cramer's Rule, what is the 2x2 determinant for the numerator for the x in the system?

 

•  $\left|-4\ \ \ -2\right|$  
   $\left|-5\ \ \ -4\right|\$  
  

•  $\left|-4\ \ \ -16\right|$  
   $\left|-5\ \ -26\right|$  
  

•  $\left|-16\ \ \ -2\right|$  
   $\left|-26\ \ \ \ -4\right|$  
  

•  $\left|-4\ \ -4\right|$  
   $\left|-2\ \ -5\right|$  
  

When setting up Cramer's Rule, what is the 2x2 determinant for the numerator for the y in the system?

 

•  $\left|-4\ \ \ -2\right|$  
   $\left|-5\ \ \ -4\right|\$  
  

•  $\left|-4\ \ \ -16\right|$  
   $\left|-5\ \ -26\right|$  
  

•  $\left|-16\ \ \ -2\right|$  
   $\left|-26\ \ \ \ -4\right|$  
  

•  $\left|-4\ \ -4\right|$  
   $\left|-2\ \ -5\right|$  
  

Subtract

• 3    -8
  0   -1
• 3   -4
  8  -13
• -3   8
  0    1
• 3   -8
  -8    1

Solve system by using Cramer's Rule. Answers are written in the following form (x,y)
 $4x+6y=3$  
 $8x-3y=1$  

•  $\left(\frac{1}{4},\frac{1}{3}\right)$  

•  $\left(-\frac{1}{3},\frac{1}{4}\right)$  

•  $\left(\frac{1}{3},\frac{1}{4}\right)$  

•  $\left(\frac{1}{4},-\frac{1}{3}\right)$  

What size is this matrix?

• 2x2

• 2x3

• 3x2

• 1x6