Finding Axis of Symmetry and Vertex

A parabola has a vertex at (-3,2).
Where is the axis of symmetry?

• y = -2
• x = 3
• x = -3
• y = 2

What is the "formula" for finding the axis of symmetry? 

•  $y=ax^2+bx+c$  

•  $x=\frac{-b}{2a}$  

•  $y=mx+b$  

•  $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$  

Find the axis of symmetry for  $y=x^2-8x+15$  

• x = -4

• x = 4

• y = 4

• y = -4

Tags

CCSS.HSA.REI.B.4

Find the axis of symmetry of
 $y=3x^2-6x+4$  

•  $x=1$ 

•  $x=-6$  

•  $x=2$ 

•  $x=-1$  

Tags

CCSS.HSA.REI.B.4

Find the vertex for  $y=x^2-8x+15$  

• (-4, 63)

• (-4, 31)

• (4, -1)

• (4, -31)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.B.3

Find the vertex of  $y=3x^2-6x+4$   

•  $\left(1,\ 1\right)$  

•  $\left(1,\ 7\right)$  

•  $\left(2,\ 4\right)$  

•  $\left(-2,\ 28\right)$  

Tags

CCSS.HSA.REI.B.4

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7