s e n θ = 3 2 sen\theta=\frac{\sqrt{3}}{2} s e n θ = 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> sus soluciones son

θ = 60 ° y 120 ° \theta=\ 60°\ y\ 120° θ = 6 0 ° y 1 2 0 °

θ = 30 ° y 150 ° \theta=\ 30°\ \ \ y\ 150° θ = 3 0 ° y 1 5 0 °

θ = 210 ° y 130 ° \theta=210°\ \ y\ 130° θ = 2 1 0 ° y 1 3 0 °

Calcula el valor del ángulo s e n θ = − 2 2 sen\theta=-\frac{\sqrt{2}}{2} s e n θ = − 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

θ = 225 ° y 315 ° \theta=\ 225°\ y\ 315°\ θ = 2 2 5 ° y 3 1 5 °

θ = 112 ° y 213 ° \theta=112°\ y\ \ 213° θ = 1 1 2 ° y 2 1 3 °

θ = 187 ° y 224 ° \theta=\ 187°\ y\ 224° θ = 1 8 7 ° y 2 2 4 °

s e n θ = 3 2 sen\theta=\frac{\sqrt{3}}{2} s e n θ = 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> sus soluciones son

θ = 60 ° y 120 ° \theta=\ 60°\ y\ 120° θ = 6 0 ° y 1 2 0 °

θ = 30 ° y 150 ° \theta=\ 30°\ \ \ y\ 150° θ = 3 0 ° y 1 5 0 °

θ = 210 ° y 130 ° \theta=210°\ \ y\ 130° θ = 2 1 0 ° y 1 3 0 °

cos ⁡ θ = − 1 \cos\theta=-1 cos θ = − 1

θ = 180 ° \theta=180°\ θ = 1 8 0 °

θ = 360 ° \theta=360° θ = 3 6 0 °

ECUACIONES TRIGONOMETRICAS

Authored by RAMIRO VILLALVA

Mathematics

12th Grade

Used 145+ times

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FILL IN THE BLANKS QUESTION

1 min • 1 pt

Hallar el valor de x de la siguiente ecuación trigonométrica.
$\frac{1+2\cos\ x}{2}=1$

(a)

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Hallar el valor de x de la siguiente ecuación trigonométrica.
$\tan\ x\ -\ \cot\ x\ =\ 0$

(a)

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Hallar el valor de x de la siguiente ecuación trigonométrica.
$8\ sen\ x\ \ =\ 2+\frac{4}{\csc\ x}$

(a)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$sen\theta=\frac{\sqrt{3}}{2}$ sus soluciones son

$\theta=\ 30°\ \ \ y\ 150°$

$\theta=210°\ \ y\ 130°$

$\theta=\ 60°\ y\ 120°$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Calcula el valor del ángulo $sen\theta=-\frac{\sqrt{2}}{2}$

$\theta=\ 225°\ y\ 315°\$

$\theta=112°\ y\ \ 213°$

$\theta=\ 187°\ y\ 224°$

No existe

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$3Tan^2\theta-1=0,\ tiene\ como\ soluciones$

{30º,150º}

{30º,210º}

{150º, 210º}

{30º,150º,210º,330º}

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Cos^2\theta-\frac{1}{4}=0,\ es$ El número de soluciones de la ecuación

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$sen\theta=\frac{\sqrt{3}}{2}$ sus soluciones son

$\theta=\ 30°\ \ \ y\ 150°$

$\theta=210°\ \ y\ 130°$

$\theta=\ 60°\ y\ 120°$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\theta=-1$

$\theta=180°\$

$\theta=0°$

$\theta=360°$

10.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Hallar el valor de x de la siguiente ecuación trigonométrica.
$sen^2\ x\ +\ \cos\ x\ +\ 1=0$

(a)

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ECUACIONES TRIGONOMETRICAS

Hallar el valor de x de la siguiente ecuación trigonométrica. 1+2cos⁡ x2=1\frac{1+2\cos\ x}{2}=121+2cos x​=1 (a)

Hallar el valor de x de la siguiente ecuación trigonométrica. tan⁡ x − cot⁡ x = 0\tan\ x\ -\ \cot\ x\ =\ 0tan x − cot x = 0 (a)

Hallar el valor de x de la siguiente ecuación trigonométrica. 8 sen x = 2+4csc⁡ x8\ sen\ x\ \ =\ 2+\frac{4}{\csc\ x}8 sen x = 2+csc x4​ (a)

senθ=32sen\theta=\frac{\sqrt{3}}{2}senθ=23​​ sus soluciones son

Calcula el valor del ángulo senθ=−22sen\theta=-\frac{\sqrt{2}}{2}senθ=−22​​

3Tan2θ−1=0, tiene como soluciones3Tan^2\theta-1=0,\ tiene\ como\ soluciones3Tan2θ−1=0, tiene como soluciones

Cos2θ−14=0, esCos^2\theta-\frac{1}{4}=0,\ esCos2θ−41​=0, es El número de soluciones de la ecuación

senθ=32sen\theta=\frac{\sqrt{3}}{2}senθ=23​​ sus soluciones son

cos⁡θ=−1\cos\theta=-1cosθ=−1

Hallar el valor de x de la siguiente ecuación trigonométrica. sen2 x + cos⁡ x + 1=0sen^2\ x\ +\ \cos\ x\ +\ 1=0sen2 x + cos x + 1=0 (a)

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Hallar el valor de x de la siguiente ecuación trigonométrica.
$\frac{1+2\cos\ x}{2}=1$

(a)

Hallar el valor de x de la siguiente ecuación trigonométrica.
$\tan\ x\ -\ \cot\ x\ =\ 0$

(a)

Hallar el valor de x de la siguiente ecuación trigonométrica.
$8\ sen\ x\ \ =\ 2+\frac{4}{\csc\ x}$

(a)

$sen\theta=\frac{\sqrt{3}}{2}$ sus soluciones son

Calcula el valor del ángulo $sen\theta=-\frac{\sqrt{2}}{2}$

$3Tan^2\theta-1=0,\ tiene\ como\ soluciones$

$Cos^2\theta-\frac{1}{4}=0,\ es$ El número de soluciones de la ecuación

$sen\theta=\frac{\sqrt{3}}{2}$ sus soluciones son

$\cos\theta=-1$

Hallar el valor de x de la siguiente ecuación trigonométrica.
$sen^2\ x\ +\ \cos\ x\ +\ 1=0$

(a)