Solving Radical Equations

Which of the following is NOT a radical equation?

• $\sqrt{x}-5\ =-1$

• $x\sqrt{3}+\ 7\ =\ 4$

• $^3\sqrt{x-7}=2$

• $8\sqrt{x}-6\ =1$

How will determine if the given equation is a radical equation?

• There is a variable in the radicand

• The highest degree is 2

• It is written in the form $a\sqrt{x}+b\ =0$

• The highest index is 2

Which of the following radical equations will have x = 9 as the solution?

• $\sqrt{x}-5=-2$

• $\sqrt{x-1}=8$

• $2\sqrt{x}-18=0$

• $\sqrt{2x-1}=\sqrt{x-10}$

What is the first step in solving the equation?

 $\sqrt{x+1}-2=5$ 

• Multiply both sides of the equation by -2.

• Add – 5 to both sides of the equation.

• Add 2 to both sides of the equation.

• Square both sides of the equation.

What must be done to eliminate the radical sign in the equation $^3\sqrt{x-1}=2$ ?

• Cube both sides of the equation.

• Square both sides of the equation.

• Double both sides of the equation.

• Divide both sides of the equation by 2.

What is the value of x in the equation  $\sqrt{x}-3=0?$  

• 3

• 6

• 9

• 12

Find the value of x in the equation  $\sqrt{x-1}=4$  .

• 5

• 15

• 17

• 25

Solve the value of x in the equation  $\sqrt{\ 3x-4}=\sqrt{\ 2x+9}$  .

• 5

• 7

• 10

• 13