y = 4 s e n x y=4senx y = 4 s e n x ¿Cuál es su derivada?

y ′ = 4 cos ⁡ x y'=4\cos x y ′ = 4 cos x

y ′ = − 4 cos ⁡ x y'=-4\cos x y ′ = − 4 cos x

y ′ = cos ⁡ 4 x y'=\cos\ 4x y ′ = cos 4 x

f ( x ) = 5 ( x − 2 ) − 2 x f\left(x\right)=5\left(x-2\right)-2x f ( x ) = 5 ( x − 2 ) − 2 x Obtén el punto máximo o mínimo de la función

P m a ˊ x ( 0 , − 10 ) Pmáx\left(0,\ -10\right) P m a ˊ x ( 0 , − 1 0 )

P m ı ˊ n ( 10 3 , 0 ) Pmín\ \left(\frac{10}{3},\ 0\right) P m ı ˊ n ( 3 1 0 , 0 )

Obtén la derivada de y = 3 8 x − 2 y=3\sqrt{8x-2} y = 3 8 x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

y ′ = 12 8 x − 2 y'=\frac{12}{\sqrt{8x-2}} y ′ = 8 x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 2

y ′ = 8 2 8 x − 2 y'=\frac{8}{2\sqrt{8x-2}} y ′ = 2 8 x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 8

y ′ = 12 8 x y'=\frac{12}{\sqrt{8x}} y ′ = 8 x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 2

Derivadas

Authored by Socorro Gonzalez

Mathematics

University - Professional Development

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10 questions

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

Deriva la función
$f\left(x\right)=4x^2-6x$

$f'\left(x\right)=8x-6$

$f'\left(x\right)=8x^2-6$

$f'\left(x\right)=4x-6$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$y=\left(3x-4\right)^2$
Deriva la función

$y'=2\left(3\right)^2$

$y'=2\left(3x-4\right)$

$y'=6\left(3x-4\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Son aquellos puntos donde existen máximos, mínimos o puntos de inflexión

Raíces de la función

Puntos críticos de la función

Intersecciones de la función

MULTIPLE CHOICE QUESTION

1 min • 1 pt

La pendiente de la tangente a la curva $y=3x^2-5$ , en x = - 2

m = 12

m = - 12

m = 7

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$y=4senx$

¿Cuál es su derivada?

$y'=4\cos x$

$y'=-4\cos x$

$y'=\cos\ 4x$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$f\left(x\right)=5\left(x-2\right)-2x$
Obtén el punto máximo o mínimo de la función

No tiene puntos críticos

$Pmáx\left(0,\ -10\right)$

$Pmín\ \left(\frac{10}{3},\ 0\right)$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$f\left(x\right)=\ln\left(6x^2-4x\right)$
Derivada de la función

$f'\left(x\right)=\frac{12x}{6x^2-4x}$

$f'\left(x\right)=\frac{\left(6x-2\right)}{3x^2-2x}$

$f'\left(x\right)=\ln\left(12x-4\right)$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$f\left(x\right)=\frac{\left(5x^4-3x^3+8x^2\right)}{x^2}$
Es la derivada de la función

$f'\left(x\right)=\frac{\left(20x^3-9x^2+16x\right)}{2x}$

$f'\left(x\right)=10x-3$

$f'\left(x\right)=5x^2-3x+8$

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Obtén la derivada de

$y=3\sqrt{8x-2}$

$y'=\frac{12}{\sqrt{8x-2}}$

$y'=\frac{8}{2\sqrt{8x-2}}$

$y'=\frac{12}{\sqrt{8x}}$

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Derivadas

Deriva la función f(x)=4x2−6xf\left(x\right)=4x^2-6xf(x)=4x2−6x

y=(3x−4)2y=\left(3x-4\right)^2y=(3x−4)2 Deriva la función

Son aquellos puntos donde existen máximos, mínimos o puntos de inflexión

La pendiente de la tangente a la curva y=3x2−5y=3x^2-5y=3x2−5 , en x = - 2

y=4senxy=4senxy=4senx ¿Cuál es su derivada?

f(x)=5(x−2)−2xf\left(x\right)=5\left(x-2\right)-2xf(x)=5(x−2)−2x Obtén el punto máximo o mínimo de la función

f(x)=ln⁡(6x2−4x)f\left(x\right)=\ln\left(6x^2-4x\right)f(x)=ln(6x2−4x) Derivada de la función

Es el valor de la pendiente de la tangente en los puntos críticos

f(x)=(5x4−3x3+8x2)x2f\left(x\right)=\frac{\left(5x^4-3x^3+8x^2\right)}{x^2}f(x)=x2(5x4−3x3+8x2)​ Es la derivada de la función

Obtén la derivada de y=38x−2y=3\sqrt{8x-2}y=38x−2​

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Discover more resources for Mathematics

Deriva la función
$f\left(x\right)=4x^2-6x$

$y=\left(3x-4\right)^2$
Deriva la función

La pendiente de la tangente a la curva $y=3x^2-5$ , en x = - 2

$y=4senx$

¿Cuál es su derivada?

$f\left(x\right)=5\left(x-2\right)-2x$
Obtén el punto máximo o mínimo de la función

$f\left(x\right)=\ln\left(6x^2-4x\right)$
Derivada de la función

$f\left(x\right)=\frac{\left(5x^4-3x^3+8x^2\right)}{x^2}$
Es la derivada de la función

Obtén la derivada de

$y=3\sqrt{8x-2}$