Parabola, hyperbola

Parabola, hyperbola

9th Grade

14 Qs

quiz-placeholder

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Parabola, hyperbola

Parabola, hyperbola

Assessment

Quiz

Mathematics

9th Grade

Medium

Created by

Martina Mlynkova

Used 7+ times

FREE Resource

14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 (x+1)225(y+3)216=1\frac{\left(x+1\right)^2}{25}-\frac{\left(y+3\right)^2}{16}=1  
směrnice jedné z asymptot u této hyperboly je

 45\frac{4}{5}  

 54\frac{5}{4}  

 1625\frac{16}{25}  

 2516\frac{25}{16}  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 (x2)29(y1)249=1\frac{\left(x-2\right)^2}{9}-\frac{\left(y-1\right)^2}{49}=1  
směrnice jedné z asymptot u této hyperboly je

 73\frac{7}{3}  

 37\frac{3}{7}  

 499\frac{49}{9}  

 949\frac{9}{49}  

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 (x2)29(y1)249=1\frac{\left(x-2\right)^2}{9}-\frac{\left(y-1\right)^2}{49}=1  
parametr e (excentricita) je roven

 58\sqrt{58}  

 40\sqrt{40}  

 40\sqrt{-40}  

 22  

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 (x5)215(y+2)26=1\frac{\left(x-5\right)^2}{15}-\frac{\left(y+2\right)^2}{6}=1  
parametr e (excentricita) je roven

 21\sqrt{21}  

 33  

 15+6\sqrt{15}+\sqrt{6}  

 156\sqrt{15}-\sqrt{6}  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 x212y23=1\frac{x^2}{12}-\frac{y^2}{3}=1  
obecná rovnice této hyperboly je

 x24y212=0x^2-4y^2-12=0  

 x24y2+12=0x^2-4y^2+12=0  

 4x2y212=04x^2-y^2-12=0  

 x24y21=0x^2-4y^2-1=0  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

V hyperbole platí: S[1,2], a=2, b=3S[1,-2],\ a=2,\ b=\sqrt{3}  


Středová rovnice je tedy:

 (x1)24(y+2)23=1\frac{\left(x-1\right)^2}{4}-\frac{\left(y+2\right)^2}{3}=1  

 (x+1)24(y2)23=1\frac{\left(x+1\right)^2}{4}-\frac{\left(y-2\right)^2}{3}=1  

 (x1)22(y+2)23=1\frac{\left(x-1\right)^2}{2}-\frac{\left(y+2\right)^2}{\sqrt{3}}=1  

 (x1)24(y+2)23=0\frac{\left(x-1\right)^2}{4}-\frac{\left(y+2\right)^2}{3}=0  

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 k=32k=\frac{3}{2}  

jedna z asymptot má směrnici k, která rovnice hyperboly by mohla vyhovovat?

 x24y29=1\frac{x^2}{4}-\frac{y^2}{9}=1  

 x22y23=1\frac{x^2}{2}-\frac{y^2}{3}=1  

 x29y24=1\frac{x^2}{9}-\frac{y^2}{4}=1  

 x23y22=1\frac{x^2}{3}-\frac{y^2}{2}=1  

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