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Topic 6 Review Sheet

Authored by Alia Jackson

Physics

10th - 12th Grade

Used 9+ times

Topic 6 Review Sheet
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18 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which quantity has both a magnitude and a direction?

energy

impulse

work

power

Answer explanation

Energy, work, and power are all SCALAR quantities that only have a magnitude. Only impulse has both a magnitude and a direction.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A 3.0-kilogram object is acted upon by an impulse having a magnitude of 15 newton seconds. What is the magnitude of the object's change in momentum due to this impulse?

45 kg m/s

15 kg m/s

3.0 kg m/s

5.0 kg m/s

Answer explanation

Remember, impulse = change in momentum. So if the impulse was 15, then the change in momentum is 15!

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A 5.00-kilogram block slides along a horizontal, frictionless surface at 10.0 meters per second for 4.00 seconds. What is the magnitude of the block's momentum?

50.0 kg m/s

12.5 kg m/s

200 kg m/s

20.0 kg m/s

Answer explanation

p = mv

p = (5kg)(10m/s) - 50 kg m/s

The time was extra information!

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When a 1.0-kilogram cart moving with a speed of 0.50 meter per second on a horizontal surface collides with a second 1.0-kilogram cart initially at rest, the carts lock together. What is the speed of the combined carts after the collision? [Neglect friction.]

0 m/s

0.50 m/s

0.25 m/s

1.0 m/s

Answer explanation

p(before) = p(after)

(1kg)(0.50m/s) + (1.0kg)(0m/s) = (1kg +1kg)v

.5 = 2v

v = 0.25 m/s

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The diagram below shows an 8.0-kilogram cart moving to the right at 4.0 meters per second about to make a head-on collision with a 4.0-kilogram cart moving to the left at 6.0 meters per second. After the collision, the 4.0-kilogram cart moves to the right at 3.0 meters per second. What is the velocity of the 8.0-kilogram cart

after the collision?

5.5 m/s, right

5.5 m/s, left

0.50 m/s, right

0.50 m/s, left

Answer explanation

p(before) = p(after)

(8kg)(4m/s) + (4kg)(-6m/s) = (8kg)v + (4kg)(3m/s)

32 + (-24) = 8v + 12

8 = 8v +12

-4 = 8v

-0.5 m/s = v

The negative means to the left!

Watch your signs!!

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which graph best represents the greatest amount of work?

Media Image
Media Image
Media Image
Media Image

Answer explanation

Work is the area under a force vs. distance graph - so just look for the largest area - you can calculate if you feel it necessary.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much work is done by the force lifting a 0.1-kilogram hamburger vertically upward at constant velocity 0.3 meter from a table?

0.4 J

0.1 J

0.03 J

0.3 J

Answer explanation

W = Fd

W = (0.1kg x 9.81 m/s2)(0.3m)

W = 0.3 J


You must turn the mass in kg into a force before finding the work done. Since the burger was lifted vertically, the work done was against gravity, so just find the weight!

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