
Topic 6 Review Sheet
Authored by Alia Jackson
Physics
10th - 12th Grade
Used 9+ times

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18 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which quantity has both a magnitude and a direction?
energy
impulse
work
power
Answer explanation
Energy, work, and power are all SCALAR quantities that only have a magnitude. Only impulse has both a magnitude and a direction.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A 3.0-kilogram object is acted upon by an impulse having a magnitude of 15 newton seconds. What is the magnitude of the object's change in momentum due to this impulse?
45 kg m/s
15 kg m/s
3.0 kg m/s
5.0 kg m/s
Answer explanation
Remember, impulse = change in momentum. So if the impulse was 15, then the change in momentum is 15!
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A 5.00-kilogram block slides along a horizontal, frictionless surface at 10.0 meters per second for 4.00 seconds. What is the magnitude of the block's momentum?
50.0 kg m/s
12.5 kg m/s
200 kg m/s
20.0 kg m/s
Answer explanation
p = mv
p = (5kg)(10m/s) - 50 kg m/s
The time was extra information!
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When a 1.0-kilogram cart moving with a speed of 0.50 meter per second on a horizontal surface collides with a second 1.0-kilogram cart initially at rest, the carts lock together. What is the speed of the combined carts after the collision? [Neglect friction.]
0 m/s
0.50 m/s
0.25 m/s
1.0 m/s
Answer explanation
p(before) = p(after)
(1kg)(0.50m/s) + (1.0kg)(0m/s) = (1kg +1kg)v
.5 = 2v
v = 0.25 m/s
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The diagram below shows an 8.0-kilogram cart moving to the right at 4.0 meters per second about to make a head-on collision with a 4.0-kilogram cart moving to the left at 6.0 meters per second. After the collision, the 4.0-kilogram cart moves to the right at 3.0 meters per second. What is the velocity of the 8.0-kilogram cart
after the collision?
5.5 m/s, right
5.5 m/s, left
0.50 m/s, right
0.50 m/s, left
Answer explanation
p(before) = p(after)
(8kg)(4m/s) + (4kg)(-6m/s) = (8kg)v + (4kg)(3m/s)
32 + (-24) = 8v + 12
8 = 8v +12
-4 = 8v
-0.5 m/s = v
The negative means to the left!
Watch your signs!!
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which graph best represents the greatest amount of work?
Answer explanation
Work is the area under a force vs. distance graph - so just look for the largest area - you can calculate if you feel it necessary.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How much work is done by the force lifting a 0.1-kilogram hamburger vertically upward at constant velocity 0.3 meter from a table?
0.4 J
0.1 J
0.03 J
0.3 J
Answer explanation
W = Fd
W = (0.1kg x 9.81 m/s2)(0.3m)
W = 0.3 J
You must turn the mass in kg into a force before finding the work done. Since the burger was lifted vertically, the work done was against gravity, so just find the weight!
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